[英]MongoDB: How to find _id $in array of objects?
I have a "group" collection which groups documents from another "item" collection. 我有一个“组”集合,该集合将另一个“项目”集合中的文档分组。 The group
collection is simply an array of ObjectId's from the item
collection, however I want to make the objects in the group
array more complex and still be able to use the $in
and $nin
operators. group
集合只是item
集合中ObjectId的数组,但是我想使group
数组中的对象更复杂,并且仍然能够使用$in
和$nin
运算符。
How can I use $in
when changing the value used with the $in
operator to an object instead of only an ObjectId? 将$in
运算符使用的值更改为对象而不是仅ObjectId时,如何使用$in
?
// current group document
{
_id: ObjectId(...),
items: [
ObjectId(...),
ObjectId(...)
]
}
// current item find query
db.item.find({ _id : { $in: group.items } }
I would like to change the group
document to look like the following 我想将group
文档更改为如下所示
{
_id: ObjectId(...),
items: [
{ _id : ObjectId(...), name: '...' },
{ _id : ObjectId(...), name: '...' }
]
}
Transform your group array to a simple array of ids to use for your find(): 将您的组数组转换为一个简单的ID数组,以用于find():
// revised item find logic
var itemGroupItemIds = group.items.map(function(item){
return item._id
});
db.item.find({ _id : { $in: itemGroupItemIds } });
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