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java.sql.SQLException:找不到列“ JOB_ID”

[英]java.sql.SQLException: Column 'JOB_ID' not found

I am using Java8 with JPA2/Hibernate5, Spring4 and mySQL. 我正在将Java8与JPA2 / Hibernate5,Spring4和mySQL一起使用。

If anyone can help, I would appreciate it. 如果有人可以提供帮助,我将不胜感激。

I have the following tables. 我有下表。

+--------+          +------------+        +---------+
| job    |          | person_job |        | person  |
+--------+          +------------+        +---------+
|  ID    |          |  JOB_ID    |        |   ID    |
|        |          |  PER_ID    |        |         |
+--------+          +------------+        +---------+

A person can have many jobs . 一个person可以做很多jobs

Job.java Job.java

@ManyToOne(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
@JoinTable(name = "person_job", joinColumns = {
        @JoinColumn(name = "PER_ID", referencedColumnName = "ID") }, inverseJoinColumns = {
                @JoinColumn(name = "JOB_ID", referencedColumnName = "ID", unique = true) })
private Person person;

The following SQL works fine when I run it directly against the database: 当直接对数据库运行以下SQL时,它运行良好:

select
         e.*, p.*
     from
         www.job as e  
     inner join
         www.person_job as pj 
             on e.id=pj.JOB_ID  
     inner join
         www.person as p 
             on pj.PER_ID=p.ID  
...

When I run a native query (with the above sql), I get the following error: 当我运行本机查询(使用上述sql)时,出现以下错误:

java.sql.SQLException: Column 'JOB_ID' not found. java.sql.SQLException:找不到列“ JOB_ID”。

In Job.java , if I swap the JOB_ID and PER_ID around in the @JoinTable , then I get: Job.java,如果我换了JOB_IDPER_ID在周围@JoinTable ,然后我得到:

java.sql.SQLException: Column 'PER_ID' not found. java.sql.SQLException:找不到列“ PER_ID”。

Because the above SQL runs fine against the database, I think the problem is with join configuration in Job.java . 因为上述SQL在数据库上运行良好,所以我认为问题出在Job.java中的联接配置上。


UPDATE 更新

I also have the following that works correctly: 我也有以下内容可以正常工作:

+--------+          +--------------+        +----------+
| job    |          | job_location |        | location |
+--------+          +--------------+        +----------+
|  ID    |          |  JOB_ID      |        |   ID     |
|        |          |  LOC_ID      |        |          |
+--------+          +--------------+        +----------+

A job can have many locations . 一份job可以有很多locations

jobs.java Jobs.java

@OneToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
@JoinTable(name = "job_location", joinColumns = {
        @JoinColumn(name = "JOB_ID", referencedColumnName = "ID") }, inverseJoinColumns = {
                @JoinColumn(name = "LOC_ID", referencedColumnName = "ID", unique = true) })
private Set<Location> locations;

UPDATE 更新

I only get this error when I execute a native query. 我仅在执行本机查询时收到此错误。 When I do the following fr example, it works perfectly. 当我做下面的例子时,它可以完美地工作。

    return (T) entityManager.find(entityClass, id);

Is there something wrong with my native query? 我的本机查询出问题了吗? (This query works if I don't have the person column on Jobs.java ). (如果我在Jobs.java上没有person列,则此查询有效)。

    StringBuilder sb = new StringBuilder();
    sb.append(" select e.* ");
    sb.append(" from ");
    sb.append("    www.job as e ");
    //sb.append(" inner join www.person_job as pj on e.id = pj.JOB_ID ");
    //sb.append(" inner join www.person as p on pj.PER_ID = p.id ");
    sb.append("  where e.id = :id ");
    Query q = entityManager.createNativeQuery(sb.toString(), JobWithDistance.class);
    q.setParameter("id", id);
    List<Job> jobs = (List<Job>) q.getResultList();

Adding the 2 commented out lines makes no difference. 添加2条注释掉的行没有区别。

SOLUTION: 解:

I needed to change: 我需要更改:

sb.append(" select e.* ");

to

sb.append(" select * ");

Try with this 试试这个

// in Job entity
@ManyToOne(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
@JoinTable(name = "person_job", joinColumns = { @JoinColumn(name = "JOB_ID") }, 
                                inverseJoinColumns = { @JoinColumn(name = "PER_ID") }
)
private Person person;

...

// in Person entity
@OneToMany(mappedBy = "person")
private List<Job> jobs;

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