[英]java.sql.SQLException: Column 'JOB_ID' not found
我正在将Java8与JPA2 / Hibernate5,Spring4和mySQL一起使用。
如果有人可以提供帮助,我将不胜感激。
我有下表。
+--------+ +------------+ +---------+
| job | | person_job | | person |
+--------+ +------------+ +---------+
| ID | | JOB_ID | | ID |
| | | PER_ID | | |
+--------+ +------------+ +---------+
一个person
可以做很多jobs
。
Job.java
@ManyToOne(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
@JoinTable(name = "person_job", joinColumns = {
@JoinColumn(name = "PER_ID", referencedColumnName = "ID") }, inverseJoinColumns = {
@JoinColumn(name = "JOB_ID", referencedColumnName = "ID", unique = true) })
private Person person;
当直接对数据库运行以下SQL时,它运行良好:
select
e.*, p.*
from
www.job as e
inner join
www.person_job as pj
on e.id=pj.JOB_ID
inner join
www.person as p
on pj.PER_ID=p.ID
...
当我运行本机查询(使用上述sql)时,出现以下错误:
java.sql.SQLException:找不到列“ JOB_ID”。
在Job.java,如果我换了JOB_ID
和PER_ID
在周围@JoinTable
,然后我得到:
java.sql.SQLException:找不到列“ PER_ID”。
因为上述SQL在数据库上运行良好,所以我认为问题出在Job.java中的联接配置上。
更新
我也有以下内容可以正常工作:
+--------+ +--------------+ +----------+
| job | | job_location | | location |
+--------+ +--------------+ +----------+
| ID | | JOB_ID | | ID |
| | | LOC_ID | | |
+--------+ +--------------+ +----------+
一份job
可以有很多locations
。
Jobs.java
@OneToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
@JoinTable(name = "job_location", joinColumns = {
@JoinColumn(name = "JOB_ID", referencedColumnName = "ID") }, inverseJoinColumns = {
@JoinColumn(name = "LOC_ID", referencedColumnName = "ID", unique = true) })
private Set<Location> locations;
更新
我仅在执行本机查询时收到此错误。 当我做下面的例子时,它可以完美地工作。
return (T) entityManager.find(entityClass, id);
我的本机查询出问题了吗? (如果我在Jobs.java
上没有person
列,则此查询有效)。
StringBuilder sb = new StringBuilder();
sb.append(" select e.* ");
sb.append(" from ");
sb.append(" www.job as e ");
//sb.append(" inner join www.person_job as pj on e.id = pj.JOB_ID ");
//sb.append(" inner join www.person as p on pj.PER_ID = p.id ");
sb.append(" where e.id = :id ");
Query q = entityManager.createNativeQuery(sb.toString(), JobWithDistance.class);
q.setParameter("id", id);
List<Job> jobs = (List<Job>) q.getResultList();
添加2条注释掉的行没有区别。
解:
我需要更改:
sb.append(" select e.* ");
至
sb.append(" select * ");
试试这个
// in Job entity
@ManyToOne(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
@JoinTable(name = "person_job", joinColumns = { @JoinColumn(name = "JOB_ID") },
inverseJoinColumns = { @JoinColumn(name = "PER_ID") }
)
private Person person;
...
// in Person entity
@OneToMany(mappedBy = "person")
private List<Job> jobs;
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