[英]Pandas plot hist sharex=False does not behave as expected
I am trying to plot histograms of a couple of series from a dataframe.我正在尝试从数据框中绘制几个系列的直方图。 Series have different maximum values:系列有不同的最大值:
df[[
'age_sent', 'last_seen', 'forum_reply', 'forum_cnt', 'forum_exp', 'forum_quest'
]].max()
returns:返回:
age_sent 1516.564016
last_seen 986.790035
forum_reply 137.000000
forum_cnt 155.000000
forum_exp 13.000000
forum_quest 10.000000
When I tried to plot histograms I use sharex=False, subplots=True
but it looks like sharex
property is ignored:当我尝试绘制直方图时,我使用sharex=False, subplots=True
但看起来sharex
属性被忽略了:
df[[
'age_sent', 'last_seen', 'forum_reply', 'forum_cnt', 'forum_exp', 'forum_quest'
]].plot.hist(figsize=(20, 10), logy=True, sharex=False, subplots=True)
I can clearly plot each of them separately, but this is less desirable.我可以清楚地分别绘制它们中的每一个,但这不太理想。 Also I would like to know what I am doing wrong.我也想知道我做错了什么。
The data I have is too big too be included, but it is easy to create something similar:我拥有的数据太大也无法包含在内,但很容易创建类似的内容:
ttt = pd.DataFrame({'a': pd.Series(np.random.uniform(1, 1000, 100)), 'b': pd.Series(np.random.uniform(1, 10, 100))})
Now I have:现在我有:
ttt.plot.hist(logy=True, sharex=False, subplots=True)
Check the x axis.检查 x 轴。 I want it to be this way (but using one command with subplots).我希望它是这种方式(但使用一个带有子图的命令)。
ttt['a'].plot.hist(logy=True)
ttt['b'].plot.hist(logy=True)
The sharex
(most likely) just falls through to mpl and sets if the panning / zooming one axes changes the other. sharex
(最有可能)只是落入 mpl 并设置是否平移/缩放一个轴改变另一个。
The issue you are having is that the same bins are being used for all of the histograms (which is enforced by https://github.com/pydata/pandas/blob/master/pandas/tools/plotting.py#L2053 if I am understanding the code correctly) because pandas assumes that if you multiple histograms then you are probably plotting columns of similar data so using the same binning makes them comparable.您遇到的问题是所有直方图都使用相同的 bins(这是由https://github.com/pydata/pandas/blob/master/pandas/tools/plotting.py#L2053强制执行的,如果我我正确理解代码)因为 Pandas 假设如果您有多个直方图,那么您可能正在绘制相似数据的列,因此使用相同的分箱使它们具有可比性。
Assuming you have mpl >= 1.5 and numpy >= 1.11 you should write your self a little helper function like假设你有 mpl >= 1.5 和 numpy >= 1.11 你应该给自己写一个像
import matplotlib.pyplot as plt
import matplotlib as mpl
import pandas as pd
import numpy as np
plt.ion()
def make_hists(df, fig_kwargs=None, hist_kwargs=None,
style_cycle=None):
'''
Parameters
----------
df : pd.DataFrame
Datasource
fig_kwargs : dict, optional
kwargs to pass to `plt.subplots`
defaults to {'fig_size': (4, 1.5*len(df.columns),
'tight_layout': True}
hist_kwargs : dict, optional
Extra kwargs to pass to `ax.hist`, defaults
to `{'bins': 'auto'}
style_cycle : cycler
Style cycle to use, defaults to
mpl.rcParams['axes.prop_cycle']
Returns
-------
fig : mpl.figure.Figure
The figure created
ax_list : list
The mpl.axes.Axes objects created
arts : dict
maps column names to the histogram artist
'''
if style_cycle is None:
style_cycle = mpl.rcParams['axes.prop_cycle']
if fig_kwargs is None:
fig_kwargs = {}
if hist_kwargs is None:
hist_kwargs = {}
hist_kwargs.setdefault('log', True)
# this requires nmupy >= 1.11
hist_kwargs.setdefault('bins', 'auto')
cols = df.columns
fig_kwargs.setdefault('figsize', (4, 1.5*len(cols)))
fig_kwargs.setdefault('tight_layout', True)
fig, ax_lst = plt.subplots(len(cols), 1, **fig_kwargs)
arts = {}
for ax, col, sty in zip(ax_lst, cols, style_cycle()):
h = ax.hist(col, data=df, **hist_kwargs, **sty)
ax.legend()
arts[col] = h
return fig, list(ax_lst), arts
dist = [1, 2, 5, 7, 50]
col_names = ['weibull $a={}$'.format(alpha) for alpha in dist]
test_df = pd.DataFrame(np.random.weibull(dist,
(10000, len(dist))),
columns=col_names)
make_hists(test_df)
The current answer works, but there is an easier workaround in recent versions.当前的答案有效,但在最近的版本中有更简单的解决方法。
While df.plot.hist
does not respect sharex=False
, df.plot.density
does.虽然df.plot.hist
不尊重sharex=False
,但df.plot.density
确实如此。
dist = [1, 2, 7, 50]
col_names = ['weibull $a={}$'.format(alpha) for alpha in dist]
test_df = pd.DataFrame(np.random.weibull(dist,
(10000, len(dist))),
columns=col_names)
test_df.plot.density(subplots=True, sharex=False, sharey=False, layout=(-1, 2))
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