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有没有与MATLAB“时间”函数等效的Python?

[英]Is there a Python equivalent to MATLAB 'time' function?

I'm porting a MATLAB R2011b code to Python 3.5.1. 我正在将MATLAB R2011b代码移植到Python 3.5.1。 The original MATLAB code, which was written around 10 years ago, contains a 'time' function as bellow: 大约10年前编写的原始MATLAB代码包含以下“时间”函数:

t_x=time(x,fsample);

The output is: 输出为:

debug> x
x =

  -0.067000  -0.067000  -0.068000  -0.069000  -0.069000  -0.070000  -0.070000  -0.071000  -0.071000  -0.072000

debug> fsample
fsample =  10000

debug> t_x
t_x =

    0.00000    0.10000    0.20000    0.30000    0.40000    0.50000    0.60000    0.70000    0.80000    0.90000

I'd like to do the same thing in Python, but I cannot find any equivalent function in Python. 我想在Python中做同样的事情,但在Python中找不到任何等效函数。 (The function name 'time' is too general that it's hard to search on Google.) It seems this 'time' function returns 1000/fsample (eg, if fsample=10000, then 0.1) multiplied by the index of 'x'. (函数名称“时间”太笼统,很难在Google上搜索。)看来,此“时间”函数返回1000 / fsample(例如,如果fsample = 10000,则为0.1)乘以“ x”的索引。 Does anyone know a similar function in Python? 有人知道Python中有类似的功能吗?

... Please note that this 'time' function is different from the 'time' function introduced in MATLAB R2014b: [ http://www.mathworks.com/help/matlab/ref/time.html?searchHighlight=time&s_tid=gn_loc_drop][1] ...请注意,此“时间”功能与MATLAB R2014b中引入的“时间”功能不同:[ http://www.mathworks.com/help/matlab/ref/time.html?searchHighlight=time&s_tid=gn_loc_drop ] [1]

It should be simple enough to implement a similar function. 实现类似功能应该足够简单。

For numpy arrays 对于numpy数组

import numpy as np
def time(x, fsample):
    return np.linspace(0, (1000/fsample)*(len(x) - 1), num=len(x))

For simple python lists 对于简单的python列表

def time(x, fsample):
    return [i*(1000/fsample) for i in range(len(x))]

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