用完整的特殊字符或空格将字符串数组中的句子拆分

Question

I want to split a sentence having spaces or any special character into an array of words with spaces or special character also an element of array.

Sentence like:

aman,amit and sumit went to top-up 

should be split into an array of String:

{"aman",",","amit"," ","and"," ","sumit"," ","went"," ","to"," ","top","-","up")

Please suggest any regex or logic to split the same using java.

I missed one thing in my question. I also need to split on numeric character as well.. But using split("\\b") does not split a string having something like

abc12def

into

{ "abc", "12","def") or {"abc","1","2","def")

Answer 1

It seems all you need is to match either word characters ( \\w+ ) or non-word ones ( \\W+ ). Combine these with an alternation operator and - perhaps - add a Pattern.UNICODE_CHARACTER_CLASS (or its inline/embedded version (?U) ) to make the pattern Unicode-aware:

String value = "aman,amit and sumit went to top-up";
String pattern = "(?U)\\w+|\\W+";
List<String> lst = new ArrayList<>();
Pattern p = Pattern.compile(pattern);
Matcher m = p.matcher(value);
while (m.find())
    lst.add(m.group(0));
System.out.println(lst);

See the Java demo

Answer 2

I hope the below code snippet helps you solve this.

public static void main(final String[] args) {
        String message = "aman,amit and sumit went to top-up";
        String[] messages = message.split("\\b");
        for(String string : messages) {
            System.out.println(string);
        }
    }