用完整的特殊字符或空格将字符串数组中的句子拆分

Question

我想将具有空格或任何特殊字符的句子拆分成具有空格或特殊字符也是数组元素的单词数组。

句子如下：

aman,amit and sumit went to top-up 

应拆分为String数组：

{"aman",",","amit"," ","and"," ","sumit"," ","went"," ","to"," ","top","-","up")

请建议使用Java将任何正则表达式或逻辑拆分为正则表达式。

我错过了我的问题的一件事。 我还需要对数字字符进行拆分。但是使用split（“ \\ b”）不会拆分具有类似内容的字符串

abc12def

进入

{ "abc", "12","def") or {"abc","1","2","def")

Answer 1

似乎您所需要的只是匹配单词字符（ \\w+ ）或非单词字符（ \\W+ ）。 将它们与替代运算符结合在一起，并可能添加一个Pattern.UNICODE_CHARACTER_CLASS （或其内联/嵌入式版本(?U) ），以使模式可识别Unicode：

String value = "aman,amit and sumit went to top-up";
String pattern = "(?U)\\w+|\\W+";
List<String> lst = new ArrayList<>();
Pattern p = Pattern.compile(pattern);
Matcher m = p.matcher(value);
while (m.find())
    lst.add(m.group(0));
System.out.println(lst);

参见Java演示

Answer 2

希望以下代码段可以帮助您解决此问题。

public static void main(final String[] args) {
        String message = "aman,amit and sumit went to top-up";
        String[] messages = message.split("\\b");
        for(String string : messages) {
            System.out.println(string);
        }
    }