如何在typescript定义中指定松散类型的对象文字？

Question

We are writing typescript definitions for a library named args-js which parses a querystring and returns the results in an object literal. eg

?name=miriam&age=26

will return

{
  name: "miriam",
  age: 26
}

The return value is an object literal, but we can't declare the property names in advance. Is there an alternative to specifying a return value of any type?

Answer 1

如果对象的深度始终为1，则可以使用以下类型：

{[key: string]: string | boolean | number}