[英]Group by on first table and keep the highest value of the second table
Here are my tables 这是我的桌子
+----------+-----------+
| id | user_id |
+----------+-----------+
| 1 | 1 |
+----------+-----------+
| 2 | 1 |
+----------+-----------+
| 3 | 1 |
+----------+-----------+
| 4 | 2 |
+----------+-----------+
| 5 | 2 |
+----------+-----------+
| 6 | 2 |
+----------+-----------+
| 7 | 3 |
+----------+-----------+
| 8 | 3 |
+----------+-----------+
| 9 | 3 |
+----------+-----------+
My second table 我的第二张桌子
+----------+---------+
| id | score |
+----------+---------+
| 1 | 10 |
+----------+---------+
| 2 | 20 |
+----------+---------+
| 3 | 5 |
+----------+---------+
| 4 | 40 |
+----------+---------+
| 5 | 15 |
+----------+---------+
| 6 | 10 |
+----------+---------+
| 7 | 5 |
+----------+---------+
| 8 | 30 |
+----------+---------+
| 9 | 10 |
+----------+---------+
I need to select the highest score achieved by a user from these tables. 我需要从这些表中选择用户获得的最高分数。
Here is my MySql query 这是我的MySql查询
SELECT * FROM
table_1 AS t1
INNER JOIN
table_2 AS t2 ON
t1.id = t2.id
WHERE t2.score > 10
GROUP BY t1.user_id
ORDER BY t2.score DESC
My desire result is 我的愿望结果是
+----------+-----------+---------+
| id | user_id | score |
+----------+-----------+---------+
| 4 | 2 | 40 |
+----------+-----------+---------+
| 8 | 3 | 30 |
+----------+-----------+---------+
| 2 | 1 | 20 |
+----------+-----------+---------+
But what I get is 但是我得到的是
+----------+-----------+---------+
| id | user_id | score |
+----------+-----------+---------+
| 4 | 2 | 40 |
+----------+-----------+---------+
| 1 | 1 | 10 |
+----------+-----------+---------+
| 7 | 3 | 5 |
+----------+-----------+---------+
MySql is always selecting the lowest id
from table_1 when I'm using the GROUP BY
clause 当我使用GROUP BY
子句时,MySql总是从table_1中选择最低的id
。
I tried using the MAX
command like this 我尝试像这样使用MAX
命令
SELECT *, MAX(t2.score) AS max_score FROM
table_1 AS t1
INNER JOIN
table_2 AS t2 ON
t1.id = t2.id
WHERE t2.score > 10
GROUP BY t1.user_id
ORDER BY t2.score DESC
LIMIT 10
And the result I'm getting 结果我得到了
+----------+-----------+---------+-----------+
| id | user_id | score | max_score |
+----------+-----------+---------+-----------+
| 4 | 2 | 40 | 40 |
+----------+-----------+---------+-----------+
| 1 | 1 | 10 | 20 |
+----------+-----------+---------+-----------+
| 7 | 3 | 5 | 30 |
+----------+-----------+---------+-----------+
I believe the result I wish it quite easy to get but I'm nowhere there. 我相信我希望很容易得到结果,但是我无处可去。
Update 1 更新1
This question was marked duplicate but unfortunately I couldn't find any solution on that given page. 这个问题被标记为重复,但是很遗憾,在给定的页面上我找不到任何解决方案。
Here is the query that I'm trying but it fails. 这是我正在尝试的查询,但失败。
SELECT * AS max_score FROM
table_1 AS t1
INNER JOIN
(
SELECT *, MAX(score) AS max_score
FROM table_2
GROUP BY t1.user_id
) AS t2
ON
t1.id = t2.id
WHERE t2.score > 10
ORDER BY t2.score DESC
LIMIT 10
It gives me the error Unknown column t1.user_id
它给我错误Unknown column t1.user_id
I'm trying to get the highest value from the column score
which is in table_2
and group the results by user_id
which is in table_1
. 我正在尝试从table_2
的列score
获取最高的值,并将结果按table_1
user_id
分组。
The examples given on those pages target only one table and I'cant make that work on my scenario. 这些页面上给出的示例仅针对一个表,我无法在我的场景中进行。
Write a subquery that gets the max score for each user_id
. 编写一个子查询,以获取每个user_id
的最高分数。 Then join that with your tables to get the rows with that max score. 然后将其与您的表一起获得具有最高得分的行。
SELECT t1.id, t1.user_id, max_score
FROM table_1 AS t1
JOIN table_2 AS t2 ON t1.id = t2.id
JOIN (
SELECT t1.user_id, MAX(t2.score) AS max_score
FROM table_1 AS t1
JOIN table_2 AS t2 on t1.id = t2.id
GROUP BY t1.user_id) AS t_max
ON t1.user_id = t_max.user_id AND t2.score = t_max.max_score
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