在第一個表上分組，並保持第二個表的最大值

Question

這是我的桌子

+----------+-----------+
|   id     |  user_id  |
+----------+-----------+
|    1     |     1     |
+----------+-----------+
|    2     |     1     |
+----------+-----------+
|    3     |     1     |
+----------+-----------+
|    4     |     2     |
+----------+-----------+
|    5     |     2     |
+----------+-----------+
|    6     |     2     |
+----------+-----------+
|    7     |     3     |
+----------+-----------+
|    8     |     3     |
+----------+-----------+
|    9     |     3     |
+----------+-----------+

我的第二張桌子

+----------+---------+
|   id     |  score  |
+----------+---------+
|    1     |    10   |
+----------+---------+
|    2     |    20   |
+----------+---------+
|    3     |     5   |
+----------+---------+
|    4     |    40   |
+----------+---------+
|    5     |    15   |
+----------+---------+
|    6     |    10   |
+----------+---------+
|    7     |     5   |
+----------+---------+
|    8     |    30   |
+----------+---------+
|    9     |    10   |
+----------+---------+

我需要從這些表中選擇用戶獲得的最高分數。

這是我的MySql查詢

SELECT * FROM 
table_1 AS t1
INNER JOIN 
table_2 AS t2 ON 
t1.id = t2.id 
WHERE t2.score > 10
GROUP BY t1.user_id
ORDER BY t2.score DESC

我的願望結果是

+----------+-----------+---------+
|   id     |  user_id  |  score  |
+----------+-----------+---------+
|    4     |      2    |    40   |
+----------+-----------+---------+
|    8     |      3    |    30   |
+----------+-----------+---------+
|    2     |      1    |    20   |
+----------+-----------+---------+

但是我得到的是

+----------+-----------+---------+
|   id     |  user_id  |  score  |
+----------+-----------+---------+
|    4     |      2    |    40   |
+----------+-----------+---------+
|    1     |      1    |    10   |
+----------+-----------+---------+
|    7     |      3    |     5   |
+----------+-----------+---------+

當我使用GROUP BY子句時，MySql總是從table_1中選擇最低的id 。

我嘗試像這樣使用MAX命令

SELECT *, MAX(t2.score) AS max_score FROM 
table_1 AS t1
INNER JOIN 
table_2 AS t2 ON 
t1.id = t2.id 
WHERE t2.score > 10
GROUP BY t1.user_id
ORDER BY t2.score DESC
LIMIT 10

結果我得到了

+----------+-----------+---------+-----------+
|   id     |  user_id  |  score  | max_score |
+----------+-----------+---------+-----------+
|    4     |      2    |    40   |    40     |
+----------+-----------+---------+-----------+
|    1     |      1    |    10   |    20     |
+----------+-----------+---------+-----------+
|    7     |      3    |     5   |    30     |
+----------+-----------+---------+-----------+

我相信我希望很容易得到結果，但是我無處可去。

更新1

這個問題被標記為重復，但是很遺憾，在給定的頁面上我找不到任何解決方案。

這是我正在嘗試的查詢，但失敗。

SELECT * AS max_score FROM 
table_1 AS t1
INNER JOIN 
(
SELECT *, MAX(score) AS max_score
FROM table_2
GROUP BY t1.user_id
) AS t2
ON 
t1.id = t2.id 
WHERE t2.score > 10
ORDER BY t2.score DESC
LIMIT 10

它給我錯誤Unknown column t1.user_id

我正在嘗試從table_2的列score獲取最高的值，並將結果按table_1 user_id分組。

這些頁面上給出的示例僅針對一個表，我無法在我的場景中進行。

Answer 1

編寫一個子查詢，以獲取每個user_id的最高分數。 然后將其與您的表一起獲得具有最高得分的行。

SELECT t1.id, t1.user_id, max_score
FROM table_1 AS t1
JOIN table_2 AS t2 ON t1.id = t2.id
JOIN (
    SELECT t1.user_id, MAX(t2.score) AS max_score
    FROM table_1 AS t1
    JOIN table_2 AS t2 on t1.id = t2.id
    GROUP BY t1.user_id) AS t_max
ON t1.user_id = t_max.user_id AND t2.score = t_max.max_score

演示