Unity 独立播放器 Windows 桌面平台 - 如何使用 Unity C# 从双击的文件中获取路径？

Question

My Windows desktop application made in Unity can read and play audio.wav but can't open it. I want to double click a .WAV file and play it. I have done myPlayWav(string path) function. And assigned to .wav file extension to call and run my application when is double click with the mouse. But:

How I get the audio file path when my application is open and run? Do I need to include something? because there is no Unity function.

using UnityEngine;

public class AtStart : MonoBehaviour 
{    
    void Start () 
    {
        string path;
        System.Run( path ?) ...
        StartCoroutine( myPlayWav ( path) );
    }

    //...

Is better to use Awake()?

Pease edit my English.

Answer 1

Use System.Environment.CommandLine .
This returns the raw (unformatted) string of the commandline. Then use string.Split(' ') to divide it into its individual args. At index 0 there should be your application. At index 1 the file you want to open and then at further indexes other arguments.

using System;

void Start ()
{
    string[] args = Environment.CommandLine.Split(' ');
    string path = args[1];
    StartCoroutine(myPlayWav(path));
}

Note that if the application is NOT started by opening a file, args[1] will be empty.

To prevent an IndexOutOfRange exception you could do this:

using System;

void Start ()
{
    string[] args = Environment.CommandLine.Split(' ');
    if (args.Length < 1)
    {
        Debug.Log("There is no file that is trying to be opened!");
        return;
    }
    string path = args[1];
    StartCoroutine(myPlayWav(path));
}