如何遍历多个OrientDB顶点

Question

I have the following graph:

Class A Vertex = [11, 21, 51, 31, 28]
Class B Vertex = [10, 14, 4, 0]
Class C Vertex = [33, 45, 35, 37]

I have a query(Q) that filter vertex of class A:

SELECT FROM A WHERE condition

Let's say the result is [31, 28]

Now I need to filter all the vertex of class B that are related (must be an outgoing edge and may or may not be a direct relation) to at least one vertex inside the query(Q) result.

The result query should return [4, 0], because if you traverse from those vertex you will get to at least one of the desired vertex (31 or 28)

I'm not sure how to create the correct query and what is the most efficient way to do it in OrientDB. Thank you.

Answer 1

select from (traverse in() from (select from A where num in [31,28])) where @class='B'

用查询替换select from A where num in [31,28]以获得那些结果