[英]Why my regex not working in this particular case
I want get out the number after "pw=" between these text 我希望在这些文本之间输出“pw =”之后的数字
For example 例如
"blablabla pw=0.5 alg=blablalbala"
would get me 0.5 会得到我0.5
The regex that I used was: 我使用的正则表达式是:
/.*pw=+(.*)\s+alg=.*/g
In the context of javascript, I would then use that regex in match function to get the number: 在javascript的上下文中,我将在匹配函数中使用该正则表达式来获取数字:
str.match(/.*pw=+(.*)\s+alg=.*/g)
But in regex101.com, the result of matching and highlight does not match at all(The result showed that the regex is correct while highlight part not) 但是在regex101.com中,匹配和高亮的结果根本不匹配(结果显示正则表达式是正确的而高亮部分没有)
You should remove the /g
global modifier, and I suggest precising your value matching pattern to [\\d.]*
. 你应该删除/g
全局修饰符,我建议将你的值匹配模式精确到[\\d.]*
。
The point is that when a global modifier is used with String#match
, all captured group values are discarded. 关键是当全局修饰符与String#match
,将丢弃所有捕获的组值。
Use a regex like 使用正则表达式
str.match(/\bpw=([\d.]*)\s+alg=/)
^^^^^^ ^
Note that you do not need the .*
at the start and end of the pattern, String#match
does not require the full string match (unlike String#matches()
in Java). 请注意,在模式的开头和结尾不需要.*
, String#match
不需要完整的字符串匹配(与Java中的String#matches()
不同)。
var str = 'blablabla pw=0.5 alg=blablalbala'; var m = str.match(/\\bpw=([\\d.]*)\\s+alg=/); if (m) { console.log(m[1]); }
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