Javascript / Regex：Split（）在我的情况下不起作用

Question

My split() is not working when there is a space before or after each line in my variable. The code below should return (123,45,67,89) but instead it returns (1234567,89). The REGEX is the problem, probably, but I don't know how to fix it. Your help will be appreciated. Thank you,

  var keywordsArray = "1 2 3 \\n4 5\\n 6 7\\n8 9"; keywordsArray = keywordsArray.replace(/\\s\\s+/g,' ').split('\\n'); alert(keywordsArray); 

Answer 1

You can use the below approaches.

Sepearted with , (comma):

> var result = keywordsArray.split('\n')
undefined
> result
[ '1 2 3  ', '4 5', ' 6       7', '8 9' ]
>
> result = result.map(s => s.replace(/\s+/g, ''))
[ '123', '45', '67', '89' ]
>
> result.join(',')
'123,45,67,89'
>

Array of integers:

> var keywordsArray = "1 2 3  \n4 5\n 6       7\n8 9"
undefined
> keywordsArray
'1 2 3  \n4 5\n 6       7\n8 9'
>
> var result = keywordsArray.split('\n')
undefined
> result
[ '1 2 3  ', '4 5', ' 6       7', '8 9' ]
>
> result = result.map(s => parseInt(s.replace(/\s+/g, '')))
[ 123, 45, 67, 89 ]
>

Answer 2

I made it worked with your string, may be this is the hard way... everything has a plan B

 var keywordsArray = "1 2 3 \\n4 5\\n 6 7\\n8 9"; keywordsArray = keywordsArray.split('\\n').map(item => item.replace(/\\s/g,'')); console.log(keywordsArray.join(',')); 

Answer 3

Just change the regex pattern. First, remove all white space. After that, replace \\n with , .

var keywordsArray = "1 2 3  \n4 5\n 6       7\n8 9";
keywordsArray = keywordsArray.replace(/ */g,'').replace(/\n/g,',');
console.log(keywordsArray);

For more information about regex, check this link

Answer 4

The only issue with your code is that \\s is matching \\n as well while replace statement, so instead of \\s use space (' ').

Please find your code with just update mentioned above:

 var keywordsArray = "1 2 3 \\n4 5\\n 6 7\\n8 9"; keywordsArray = keywordsArray.replace(/ +/g,' ').split('\\n'); alert(keywordsArray); 

Answer 5

Try using the literal space ' ' instead of '\\s' since

/\\s/g any whitespace character

Check out regex101 the next time you get stuck -- it's really helpful!