[英]Multi-level map using stream() collect() groupingBy() and reducing()
I managed to write Collector.groupingBy(Function, groupingBy(classifier, toList())
我设法写了Collector.groupingBy(Function, groupingBy(classifier, toList())
Map<String, Map<Person.Sex, List<Person>>> groupByYearThenSex = personList.stream().collect(
groupingBy(p ->{
if(p.getYear() > 2015) return "New members";
else if(p.getYear() < 2009) return "Senior members";
else return "Normal members";
},
groupingBy(Person::getSex)
)
);
groupByYearThenSex.forEach((String y, Map<Person.Sex, List<Person>> m) ->{
System.out.println("\n" + y);
m.forEach((Person.Sex s, List<Person> p) -> {
System.out.println(" " + s);
p.forEach((Person prsn) -> {
System.out.println(" " + prsn.toString());
});
});
});
The corresponding result is: 相应的结果是:
New members
MALE
Person{name: Gawel, age: 23, sex: MALE}
Normal members
MALE
Person{name: Patryk, age: 34, sex: MALE}
Person{name: Pawel, age: 21, sex: MALE}
Person{name: Bolek, age: 12, sex: MALE}
Person{name: Lolek, age: 12, sex: MALE}
FEMALE
Person{name: Jola, age: 70, sex: FEMALE}
Person{name: Ala, age: 25, sex: FEMALE}
Senior members
FEMALE
Person{name: Iwona, age: 34, sex: FEMALE}
Person{name: Oliwia, age: 17, sex: FEMALE}
Now I'm trying to produce the multi-level map that lists only the oldest members as follows: 现在我正在尝试生成多级映射,其中仅列出最旧的成员,如下所示:
New members
MALE
Person{name: Gawel, age: 23, sex: MALE}
Normal members
MALE
Person{name: Patryk, age: 34, sex: MALE}
FEMALE
Person{name: Jola, age: 70, sex: FEMALE}
Senior members
FEMALE
Person{name: Iwona, age: 34, sex: FEMALE}
The code below does not work. 下面的代码不起作用。 I get "inference variable RR has incompatible bounds error, which is I think Function<R,RR>
=> collectingAndThen(reducing(), Optional)
. Is there any way I can reduce the stream of Persons to get the oldest ones and get the output above? 我得到“推理变量RR有不兼容的边界错误,我认为Function<R,RR>
=> collectingAndThen(reducing(), Optional)
。有没有办法我可以减少人流来获取最老的并得到上面的输出?
Map<String, Map<Person.Sex, List<Person>>> groupByYearThenSexOldest = personList.stream().collect(
groupingBy(p ->{
if(p.getYear() > 2015) return "New members";
else if(p.getYear() < 2009) return "Senior members";
else return "Normal members";
},
groupingBy(Person::getSex, collectingAndThen(
reducing((p1, p2) -> p1.getAge() > p2.getAge() ? p1 : p2),
Optional::get)
)
)
);
The problem is the type parameters of your map. 问题是地图的类型参数。 It should give you a Map<String, Map<Person.Sex, Person>>
instead of a Map<String, Map<Person.Sex, List<Person>>>
since you are reducing the list. 它应该为您提供Map<String, Map<Person.Sex, Person>>
而不是Map<String, Map<Person.Sex, List<Person>>>
因为您正在减少列表。
But you can combine the second groupingBy
collector with maxBy
and collectingAndThen
: 但是,你可以结合第二groupingBy
集电极与maxBy
和collectingAndThen
:
groupingBy(Person::getSex, collectingAndThen(maxBy(Comparator.comparingInt(Person::getAge)), Optional::get)
Sometimes if you need to group by multiple fields, you can use a list that groups the fields (assuming they have a proper equals and hashcode methods). 有时,如果您需要按多个字段进行分组,则可以使用对字段进行分组的列表(假设它们具有正确的equals和hashcode方法)。 For instance: 例如:
Function<Person, String> groupingYear = p -> {
if (p.getYear() > 2015) return "New members";
else if (p.getYear() < 2009) return "Senior members";
else return "Normal members";
};
Map<Object, Optional<Person>> map2 =
personList.stream()
.collect(groupingBy(p -> Arrays.asList(groupingYear.apply(p), p.getSex()), maxBy(Comparator.comparingInt(Person::getAge))));
which gives: 这使:
[Normal members, MALE] => Optional[Person{name='Patryk', age=34, sex=MALE}]
[Senior members, FEMALE] => Optional[Person{name='Iwona', age=34, sex=FEMALE}]
[Normal members, FEMALE] => Optional[Person{name='Jola', age=70, sex=FEMALE}]
[New members, MALE] => Optional[Person{name='Gawel', age=23, sex=MALE}]
But then you may start by using the toMap
collector and compare the ages in the merge function you supply when 2 values are grouped together: 但是,您可以从使用toMap
收集器开始,并比较在将2个值组合在一起时提供的合并函数中的年龄:
Map<Object, Person> map =
personList.stream()
.collect(toMap(p -> Arrays.asList(groupingYear.apply(p), p.getSex()),
p -> p,
(p1, p2) -> {
if(p1.getAge() > p2.getAge()) return p1;
else return p2;
},
HashMap::new));
You have an Object
as key in your Map
(the real type is awful and long to write), but what you can do is create a dedicated class MemberStatusAndSex
that combines both attributes (instead of a List
- don't forget to implement equals and hashcode for this class), and get a Map<MemberStatusAndSex, Person>
at the end. 你的Map
有一个Object
作为键(真正的类型很糟糕且写MemberStatusAndSex
长),但你可以做的是创建一个专用的类MemberStatusAndSex
,它结合了两个属性(而不是List
- 不要忘记实现equals和这个类的哈希码),并在最后得到一个Map<MemberStatusAndSex, Person>
。
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