Java Regex 提取带有可选尾部斜杠的子字符串

Question

Regex:

\/test\/(.*|\/?)

Input

/something/test/{abc}/listed

/something/test/{abc}

Expected

{abc} for both the inputs

Answer 1

This should work for you :

public static void main(String[] args) {

    String s1 = "/something/test/{abc}/listed";
    String s2 = "/something/test/{abc}";

    System.out.println(s1.replaceAll("[^{]+(\\{\\w+\\}).*", "$1"));
    System.out.println(s2.replaceAll("[^{]+(\\{\\w+\\}).*", "$1"));
}

O/P :

{abc}
{abc}

Answer 2

You need to capture all characters other than / after /test/ :

String s = "/something/test/{abc}/listed";
Pattern pattern = Pattern.compile("/test/([^/]+)"); // or "/test/\\{([^/}]+)"
Matcher matcher = pattern.matcher(s);
if (matcher.find()){
    System.out.println(matcher.group(1)); 
} 

See the online demo

Details :

• /test/ - matches /test/
• ([^/]+) - matches and captures into Group 1 one or more ( + ) (but as many as possible, since + is greedy) characters other than / (due to the negated character class [^/] ).

Note that in Java regex patterns you do not need to escape / since it is not a special character and one needs no regex delimiters.

Answer 3

正则表达式（作为 Java 字符串，带有双反斜杠）：

".*\\/test\\/([^/]*).*"