[英]calculate the total value dict
I have a problem, how to calculate the total dict of the same keys ? 我有一个问题,如何计算相同键的总字典? I have a dict: 我有一个命令:
{'learning': {'DOC1': 0.14054651081081646,
'DOC2': 0,
'DOC3': 0.4684883693693881},
'life': {'DOC1': 0.14054651081081646,
'DOC2': 0.20078072972973776,
'DOC3': 0}
}
and I hope the results as: 我希望结果为:
{'learning life': {
'DOC1': DOC1 in learning + DOC1 in life,
'DOC2': DOC2 in learning + DOC2 in life,
'DOC3': DOC3 in learning + DOC3 in life,}}
Thank you very much 非常感谢你
Pretty simple: 很简单:
for k in d['learning']:
print(d['learning'][k] + d['life'][k])
... with d
being your dict
and no error checking whatsoever (does the key exist, is it really a number, etc.). ... d
是您的dict
并且不会检查任何错误(该键是否存在,是否确实是一个数字,等等)。
d = {'learning': {'DOC1': 0.14054651081081646, 'DOC2': 0, 'DOC3': 0.4684883693693881}, 'life': {'DOC1': 0.14054651081081646, 'DOC2': 0.20078072972973776, 'DOC3': 0} } d['sum'] = [d['learning'][k] + d['life'][k] for k in d['learning']] print(d)
See a demo on ideone.com . 在ideone.com上查看演示 。
您可以使用字典理解来添加嵌套在字典d
中的所有数字,如下所示:
totals = {k: sum(v.get(k, 0) for v in d.values()) for k in d.values()[0]} # dict of totals
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