SQL查询计数出现的次数，然后按天分组，但也填写缺少的日子

Question

I have a table called diseaseScores which has calculation results. Each hour a running score is calculated ( currentScore ). The objective of this query is to group the hourly scores by the day ( obsDate ), then count the numberOfhours where the running score is at a level considered high. High is greater than 16 ( currentScore > 16 ).

My query so far is:

SELECT
    DATEADD(DAY, 0, DATEDIFF(day, 0, obsDate)) AS obsDate, 
    (CASE 
        WHEN count(id) > 12 THEN count(id) 
        ELSE 0 
     END) numOfHoursAtHigh 
FROM
    diseaseScores
WHERE 
    diseaseID = 2 
    AND siteID = 72160 
    AND numOfRotationYears = 3 
    AND currentScore > 16 
    AND month(obsDate) IN (6) 
GROUP BY
    DATEADD(DAY, 0, DATEDIFF(day, 0, obsDate)) 
ORDER BY
    DATEADD(DAY, 0, DATEDIFF(day, 0, obsDate));

The query returns results for 13 days of the month. I wish to fill the gaps so I a have a record for each of the day of the month. The gaps need to have a numOfHoursAtHigh result of 0.

How can I do this? This is for SQL Server 2008 +

The result set being returned is:

        2016-06-04 00:00:00.000     0
        2016-06-05 00:00:00.000     23
        2016-06-06 00:00:00.000     23
        2016-06-07 00:00:00.000     23
        2016-06-08 00:00:00.000     3
        2016-06-09 00:00:00.000     23
        2016-06-10 00:00:00.000     0
        2016-06-17 00:00:00.000     13
        2016-06-18 00:00:00.000     23
        2016-06-19 00:00:00.000     0
        2016-06-20 00:00:00.000     14
        2016-06-21 00:00:00.000     23
        2016-06-22 00:00:00.000     16

UPDATE : So using a modified version of knobcreekmans approach (was doubling up certain days) I now have this which does fill my gaps and works great for one month. As soon as I ask for two months worth by changing month(obsDate) IN (6) to month(obsDate) IN (6,7) it skips days if they happen to clash in month 6 and 7. Grrrrrr, am so close!

        SELECT CAST(obsDate AS DATE) as obsDate, 
            (CASE 
                WHEN COUNT(id) > 12 THEN COUNT(id) 
                ELSE 0 
              END) numOfHoursAtHigh 
        FROM diseaseScores
        WHERE diseaseID=2 
           AND siteID=72160 
           AND numOfRotationYears=3 
           AND currentScore > 16 
           AND month(obsDate) IN (6) 
          GROUP BY CAST(obsDate AS DATE) 
        UNION
        SELECT CAST(obsDate AS DATE) AS obsDate, 
            0 AS numOfHoursAtHigh 
        FROM diseaseScores
        WHERE diseaseID=2 
           AND siteID=72160 
           AND numOfRotationYears=3 
           AND currentScore <= 17       
           AND month(obsDate) IN (6)
           and day(obsDate) NOT IN      --<-- added from here
           (
        SELECT distinct day(obsDate) 
        FROM diseaseScores
        WHERE diseaseID=2 
           AND siteID=72160 
           AND numOfRotationYears=3 
           AND currentScore > 16 
           AND month(obsDate) IN (6) 
           )                           --<-- to here to omit the duplicates
        GROUP BY CAST(obsDate AS DATE)
        ORDER BY CAST(obsDate AS DATE)  

To answer to the question around the expected result. Its one record for each day of the month (or months) giving to columns. A date and then an integer for numOfHoursAtHigh eg

        2016-06-01  0
        2016-06-02  0
        2016-06-03  0
        2016-06-04  0
        2016-06-05  23
        2016-06-06  23
        2016-06-07  23
        2016-06-08  23
        2016-06-09  23
        2016-06-10  0
        2016-06-11  0
        2016-06-12  0
        2016-06-13  0
        2016-06-14  0
        2016-06-15  0
        2016-06-16  0
        2016-06-17  13
        2016-06-18  23
        2016-06-19  0
        2016-06-20  14
        2016-06-21  23
        2016-06-22  16
        2016-06-23  0
        2016-06-24  0
        2016-06-25  0
        2016-06-26  0
        2016-06-27  0
        2016-06-28  0
        2016-06-29  0
        2016-06-30  0

Answer 1

You could create another SELECT that is the same as the original, modify the part of your WHERE clause that is filtering out the results you want ( currentScore > 16 ), and then UNION them together.

SELECT CAST(obsDate AS DATE) as obsDate, 
    (CASE 
        WHEN COUNT(id) > 12 THEN COUNT(id) 
        ELSE 0 
      END) numOfHoursAtHigh 
FROM diseaseScores
WHERE diseaseID=2 
   AND siteID=72160 
   AND numOfRotationYears=3 
   AND currentScore > 16 
   AND month(obsDate) IN (6) 
  GROUP BY CAST(obsDate AS DATE) 
UNION
SELECT CAST(obsDate AS DATE) AS obsDate, 
    0 AS numOfHoursAtHigh 
FROM diseaseScores
WHERE diseaseID=2 
   AND siteID=72160 
   AND numOfRotationYears=3 
   AND currentScore < 17       --<-- note the change
   AND month(obsDate) IN (6) 
GROUP BY CAST(obsDate AS DATE)
ORDER BY CAST(obsDate AS DATE)

Answer 2

Hi,
You can have the below query,

SELECT  DS.dateadd(DAY,0, datediff(day,0, obsDate)) as obsDate,
CASE 
WHEN  DS1.COUNT(id) > 12 THEN COUNT(id)
ELSE 0
END AS numOfHoursAtHigh
  FROM diseaseScores DS
  INNER JOIN (
SELECT dateadd(DAY,0, datediff(day,0, obsDate)) AS date, COUNT(id)
FROM diseaseScores GROUP BY  date
) DS1
ON DS.date = DS1.obsDate
AND DS.diseaseID=2 
AND DS.siteID=721DS.60 
AND DS.numOfRotationYears=3 
AND DS.currentScore > 16 
AND DS.month(obsDate) IN (6) 
ORDER BY DS.obsDate;