SQL查询计数出现的次数，然后按天分组，但也填写缺少的日子

Question

我有一个名为diseaseScores的表，该表具有计算结果。 每小时计算一次跑步成绩（ currentScore ）。 该查询的目的是按小时（ obsDate ）将小时分数obsDate ，然后计算跑步分数处于较高水平的numberOfhours 。 高大于16（ currentScore > 16 ）。

到目前为止，我的查询是：

SELECT
    DATEADD(DAY, 0, DATEDIFF(day, 0, obsDate)) AS obsDate, 
    (CASE 
        WHEN count(id) > 12 THEN count(id) 
        ELSE 0 
     END) numOfHoursAtHigh 
FROM
    diseaseScores
WHERE 
    diseaseID = 2 
    AND siteID = 72160 
    AND numOfRotationYears = 3 
    AND currentScore > 16 
    AND month(obsDate) IN (6) 
GROUP BY
    DATEADD(DAY, 0, DATEDIFF(day, 0, obsDate)) 
ORDER BY
    DATEADD(DAY, 0, DATEDIFF(day, 0, obsDate));

该查询返回每月13天的结果。 我希望填补空白，所以我每个月的每一天都有一个记录。 间隙需要将numOfHoursAtHigh结果numOfHoursAtHigh 0。

我怎样才能做到这一点？ 这是针对SQL Server 2008 +

返回的结果集为：

        2016-06-04 00:00:00.000     0
        2016-06-05 00:00:00.000     23
        2016-06-06 00:00:00.000     23
        2016-06-07 00:00:00.000     23
        2016-06-08 00:00:00.000     3
        2016-06-09 00:00:00.000     23
        2016-06-10 00:00:00.000     0
        2016-06-17 00:00:00.000     13
        2016-06-18 00:00:00.000     23
        2016-06-19 00:00:00.000     0
        2016-06-20 00:00:00.000     14
        2016-06-21 00:00:00.000     23
        2016-06-22 00:00:00.000     16

更新：因此，使用经过修改的旋钮式方法（在某些日子里翻了一番），我现在有了这个方法，它确实填补了我的空白，并且可以工作一个月。 一旦我通过将month（obsDate）IN（6）更改为month（obsDate）IN（6,7）来要求两个月的价值，如果它们恰好在第6和第7个月发生冲突，它就会跳过几天。

        SELECT CAST(obsDate AS DATE) as obsDate, 
            (CASE 
                WHEN COUNT(id) > 12 THEN COUNT(id) 
                ELSE 0 
              END) numOfHoursAtHigh 
        FROM diseaseScores
        WHERE diseaseID=2 
           AND siteID=72160 
           AND numOfRotationYears=3 
           AND currentScore > 16 
           AND month(obsDate) IN (6) 
          GROUP BY CAST(obsDate AS DATE) 
        UNION
        SELECT CAST(obsDate AS DATE) AS obsDate, 
            0 AS numOfHoursAtHigh 
        FROM diseaseScores
        WHERE diseaseID=2 
           AND siteID=72160 
           AND numOfRotationYears=3 
           AND currentScore <= 17       
           AND month(obsDate) IN (6)
           and day(obsDate) NOT IN      --<-- added from here
           (
        SELECT distinct day(obsDate) 
        FROM diseaseScores
        WHERE diseaseID=2 
           AND siteID=72160 
           AND numOfRotationYears=3 
           AND currentScore > 16 
           AND month(obsDate) IN (6) 
           )                           --<-- to here to omit the duplicates
        GROUP BY CAST(obsDate AS DATE)
        ORDER BY CAST(obsDate AS DATE)  

围绕预期结果回答问题。 每个月（或几个月）每天的一个记录。 日期，然后是numOfHoursAtHigh的整数，例如

        2016-06-01  0
        2016-06-02  0
        2016-06-03  0
        2016-06-04  0
        2016-06-05  23
        2016-06-06  23
        2016-06-07  23
        2016-06-08  23
        2016-06-09  23
        2016-06-10  0
        2016-06-11  0
        2016-06-12  0
        2016-06-13  0
        2016-06-14  0
        2016-06-15  0
        2016-06-16  0
        2016-06-17  13
        2016-06-18  23
        2016-06-19  0
        2016-06-20  14
        2016-06-21  23
        2016-06-22  16
        2016-06-23  0
        2016-06-24  0
        2016-06-25  0
        2016-06-26  0
        2016-06-27  0
        2016-06-28  0
        2016-06-29  0
        2016-06-30  0

Answer 1

你可以创建另一个SELECT就是将原来一样，修改的部分WHERE被过滤掉你想要的结果（第currentScore > 16 ），然后UNION在一起。

SELECT CAST(obsDate AS DATE) as obsDate, 
    (CASE 
        WHEN COUNT(id) > 12 THEN COUNT(id) 
        ELSE 0 
      END) numOfHoursAtHigh 
FROM diseaseScores
WHERE diseaseID=2 
   AND siteID=72160 
   AND numOfRotationYears=3 
   AND currentScore > 16 
   AND month(obsDate) IN (6) 
  GROUP BY CAST(obsDate AS DATE) 
UNION
SELECT CAST(obsDate AS DATE) AS obsDate, 
    0 AS numOfHoursAtHigh 
FROM diseaseScores
WHERE diseaseID=2 
   AND siteID=72160 
   AND numOfRotationYears=3 
   AND currentScore < 17       --<-- note the change
   AND month(obsDate) IN (6) 
GROUP BY CAST(obsDate AS DATE)
ORDER BY CAST(obsDate AS DATE)

Answer 2

你好
您可以进行以下查询，

SELECT  DS.dateadd(DAY,0, datediff(day,0, obsDate)) as obsDate,
CASE 
WHEN  DS1.COUNT(id) > 12 THEN COUNT(id)
ELSE 0
END AS numOfHoursAtHigh
  FROM diseaseScores DS
  INNER JOIN (
SELECT dateadd(DAY,0, datediff(day,0, obsDate)) AS date, COUNT(id)
FROM diseaseScores GROUP BY  date
) DS1
ON DS.date = DS1.obsDate
AND DS.diseaseID=2 
AND DS.siteID=721DS.60 
AND DS.numOfRotationYears=3 
AND DS.currentScore > 16 
AND DS.month(obsDate) IN (6) 
ORDER BY DS.obsDate;