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Linux Shell脚本,用于从列表中为用户添加密码

[英]Linux Shell script to add a user with a password from a list

I'm trying to modify a script that read usernames/password from a file which is like this: 我正在尝试修改一个从文件中读取用户名/密码的脚本,如下所示:

user1 pass1
user2 pass2
user3 pass3

I can't get the script to read the space between the users and pass. 我无法获取脚本来读取用户之间的空间并通过。 What can I use to delimit this space? 我可以用什么来划定这个空间? This is my code: 这是我的代码:

for row in `cat $1`
do
  if [ $(id -u) -eq 0 ]; then


      username=${row%:*}
      password=${row#*:}
      #echo $username
      #echo $password

I know I have to change the stuff in ${row%: } and ${row%: } 我知道我必须更改$ {row%: }和$ {row%: }中的内容

What do I have to put so it sees the space between user1 pass1 ? 我必须放置什么才能看到user1 pass1之间的空间?

It would be easier to split the two fields as you read each line. 阅读每一行时,将两个字段拆分会更容易。 You can do that with read . 您可以使用read做到这一点。 It's also better to use a while loop here (a for loop requires to play with $IFS and it would also load the entire file in memory): 最好while此处使用while循环(for循环需要使用$IFS进行播放,并且还会将整个文件加载到内存中):

#!/bin/bash
if [ "$EUID" -ne 0 ]; then
    echo >&2 "You are not root"
    exit 1
fi

while read -r username password; do
    # do the useradd stuff here
done < "$1"

Notice that I also changed $(id -u) to $UID which should be faster since it does not invoke an external program. 注意,我也将$(id -u)更改$(id -u) $UID ,这应该更快,因为它不会调用外部程序。

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