使用QueryDSL，如何在子项与所有条件匹配的集合上创建表达式？

Question

Assume I have an Appointment table and a Person table, where an Appointment has many Person s.

If I wanted to find all Appointments containing at least one Person in my list I would do:

Collection<Person> personsList = getInterestedPersons();
BooleanExpresssion expr = appointment.persons.any().in(personsList)

However, what I really want to so is find all Appointments that have ALL the persons in my list.

So, how can I construct a BooleanExpression that will let me filter for all Appointments who have all the Persons?

Note: I must create a BooleanExprsesion, because this is part of a larger generic filter for Appointments, where all the BooleanExpressions get and()ed together.

Another note, I do not what to find Appointments that have only those Persons, just at least all those in the list.

Answer 1

In this case, I guess the following should work:

BooleanBuilder personClause = new BooleanBuilder();
for (Person person : personList)
{
    personClause.and(appointment.persons.contains(person));
}
query.where(personClause); // to add the clause