如何在R中转换日期？

Question

I have dataset with column Date such

1-Apr-08
18-Sep-09

And I want to transform them to

01/04/08
18/09/09

I try format(as.Date(d, "%d-%b-%y"), "%d/%m/%y") but it doesn't work

UPD I found that my code doesn't work because system language of my PC is russian. When I try to transform 1-Апр-08, it works (Апрель = April).

Answer 1

When your d is a character, you can use:

format(as.Date(d, "%d-%b-%y"), "%d/%m/%y")

If not, then use

format(as.Date(as.character(d), "%d-%b-%y"), "%d/%m/%y")

Answer 2

My code was correct. It didn't work because system language of my PC was russian. For example, When I tried to transform 1-Апр-08, it worked routinely (Апрель is April in russian)