如何在C＃中获得锯齿状数组中的元素（UNITY 3d）

Question

I created a 3d int array

public int[,,]  npcState =  new int[,,] {
    {
        {0,0}
    },{
        {1,9,1},{1,0,1},{1,1,1}
    },{
        {2,2,2},{1,1,1},{1,1,1}
    },{
        {1,1,1},{10,10}
    },{
        {8,0},{0,0},{0,0},{0,0}
    },{
        {10,7},{1,1,1},{1,1,1},{1,1,1},{1,1,1}
    },{
        {2,2,2}
    },{
        {1,1,1} ,{1,1,1}
    },{
        {8,11},{0,0},{0,0},{0,0},{0,0}
    },{
        {0,1,1},{1,1,1}
    }
};

My questions are

1.) How to assign value at run time

2.)How to check array each rows and column using loop like

for(int i =0 ; i < firstDimensionalLength ; i ++){
  for(int j =0 ; j < secondDimensionalLength; j ++){
     for(int k =0 ; k < thirdDimensionalLength; k ++){
// print (npcState[i,j,k]); 
   }
  }
}

If it constant length for all dimensional , it is easy to find elements . But if it dynamic how to find each elements in particular positions

Answer 1

EDIT: as per commenter's suggestion I am adding a compiling version of the multi-dimensional array declaration:

public int[,,] npcState =  new int[,,] {
    {
       {2,2,2},{1,1,1},{1,1,1}
    },{
        {1,9,1},{1,0,1},{1,1,1}
    },{
        {2,2,2},{1,1,1},{1,1,1}
    },{
        {2,2,2},{1,1,1},{1,1,1}
    },{
        {2,2,2},{1,1,1},{1,1,1}
    },{
        {2,2,2},{1,1,1},{1,1,1}
    },{
       {2,2,2},{1,1,1},{1,1,1}
    },{
        {2,2,2},{1,1,1},{1,1,1}
    },{
        {2,2,2},{1,1,1},{1,1,1}
    },{
        {2,2,2},{1,1,1},{1,1,1}
    }
};

If you really want to use for loop, then you can access the length of the dimensions by using GetLength() method:

var firstDimensionalLength = npcState.GetLength(0);
var secondDimensionalLength = npcState.GetLength(1);
var thirdDimensionalLength = npcState.GetLength(2);

Source

Answer 2

In case you want just to scan the entire array, try using foreach :

foreach (int item in npcState) {
  // print (item); 

  if (SomeCondition(item)) {
    ...
  }  
}

please notice, that the loop doesn't depend on array's dimensions (it will be the same for 1d, 2d, 3d etc. arrays)

Edit: if you want item's location (ie i, j, k indexes) you have to put

// In many cases you can put 0 instead of `npcState.GetLowerBound()` since 
// arrays are zero based by default
for (int i = npcState.GetLowerBound(0); i <= npcState.GetUpperBound(0); i++)
  for (int j = npcState.GetLowerBound(1); j <= npcState.GetUpperBound(1); ++j)
    for (int k = npcState.GetLowerBound(2); k <= npcState.GetUpperBound(2); ++k) {
      int item = npcState[i, j, k];
      ...
    }

Edit 2 : Since the question has been edited and ND array has been turned into jagged one the solution should have been changed as well:

  int[][][] npcState = new int[][][] {
    new int[][] {
      new int[] { 0, 0 } },
    new int[][] {
      new int[] { 1, 9, 1},
      new int[] { 1, 0, 1},
      new int[] { 1, 1, 1}, },
    new int[][] {
      new int[] { 2, 2, 2},
      new int[] { 1, 1, 1},
      new int[] { 1, 1, 1}, }, 
    // ...
  };

 // Array of array of array can be just flatten twice
 foreach (var item in npcState.SelectMany(line => line.SelectMany(row => row))) {
   ...
 }

Location preserved loop will be

 for (int i = 0; i < npcState.Length; ++i) 
   for (int j = 0; j < npcState[i].Length; ++j) 
     for (int k = 0; k < npcState[i][j].Length; ++k) {
       int item = npcState[i][j][k];
       ...   
     }