Python：从字符串列表中删除一部分字符串

Question

I used xlrd to extract a column from an excel sheet to make into a list.

from xlrd import open_workbook
book = xlrd.open_workbook("HEENT.xlsx").sheet_by_index(0)
med_name = []
for row in sheet.col(2):
    med_name.append(row)
med_school = []
for row in sheet.col(3):
    med_school.append(row)
print(med_school)

Below is a snippet of the list: med_school.

[text:'University of San Francisco', 
text: 'Harvard University', 
text:'Class of 2016, University of Maryland School of Medicine', 
text:'Class of 2015, Johns Hopkins University School of Medicine', 
text:'Class of 2014, Raymond and Ruth Perelman School of Medicine at the
University of Pennsylvania']

I want to remove "text:'Class of 2014" from each string in the list. I tried list comprehension, but I got an attribute error: 'Cell' object has no attribute 'strip'. Does anyone know of a way to create a list of medical school names that have just the medical school names without the class year and the word "text"?

Answer 1

The xlrd does not return you strings, it returns you instances of a class called Cell . This has a property value that contains the string you are seeing.

To modify these simply:

for cell in med_school:
    cell.value = cell.value[:15]

This will remove the first 15 characters ("Class of 2014, "). Alternatively you could use other approaches like string splitting (on ",") or a regex.

The point here is that you shouldn't be working directly on the values in the med_schools list, but on their .value property. Or extract it to somewhere else you could work on it.

For example, to get all of the text properties, dropping the prefix:

values = [cell.value[15:] for cell in med_schools]

Or using a regex to replace to replace only those actualling containing the offending data

values = [re.sub(r"^Class of \d{4}, ", "", cell.value) for cell in med_schools]

Answer 2

Use the given separator to cut off the head of each string. Check first to make sure it has "Class", so we know the comma-space is there.

med_school = ["text:'Class of 2016, University of Maryland School of Medicine'",  
              "text:'Class of 2015, Johns Hopkins University School of Medicine'", 
              "text:'Class of 2014, Raymond and Ruth Perelman School of Medicine at the University of Pennsylvania'",
              "text:'Class of 1989, Rush Medical School / Knox College'",
              "text:'Bernie\'s Back-Alley School of Black-Market Techniques'"
             ]

school_name = []
for first in med_school:
    name = first.value
    if ", " in name:
        cut  = name.index(", ")
        name = name[cut+2:]
    else:
        name = name[6:-1]
    school_name.append(name)

print school_name

output (with extra line feeds to improve readability):

["University of Maryland School of Medicine'",
 "Johns Hopkins University School of Medicine'",
 "Raymond and Ruth Perelman School of Medicine at the University of Pennsylvania'"
 "Rush Medical School / Knox College'", 
 "Bernie's Back-Alley School of Black-Market Techniques"]

You could also wrap the loop into a list comprehension:

school_name = [name.value[name.value.index(", ")+2:] \
                       if ", " in name \
                       else name[6:-1]   \
                   for name in med_school]

Answer 3

Change for row in sheet.col(2) to for row in sheet.col(2).value .
U will get rid of the do file type and get the actual value. Do this.

results =[] for row in sheet.col(2).value: print(row)