[英]python preserving output csv file column order
The issue is common, when I import a csv file and process it and finally output it, the order of column in the output csv file may be different from the original one,for instance: 这个问题很常见,当我导入一个csv文件并对其进行处理并最终将其输出时,输出csv文件中的列顺序可能与原始文件不同,例如:
dct={}
dct['a']=[1,2,3,4]
dct['b']=[5,6,7,8]
dct['c']=[9,10,11,12]
header = dct.keys()
rows=pd.DataFrame(dct).to_dict('records')
with open('outTest.csv', 'wb') as f:
f.write(','.join(header))
f.write('\n')
for data in rows:
f.write(",".join(str(data[h]) for h in header))
f.write('\n')
the original csv file is like: 原始的csv文件如下所示:
a,c,b
1,9,5
2,10,6
3,11,7
4,12,8
while I'd like to fixed the order of the column like the output: 而我想固定输出的列顺序:
a,b,c
1,5,9
2,6,10
3,7,11
4,8,12
and the answers I found are mostly related to pandas
, I wonder if we can solve this in another way. 我发现的答案大多与
pandas
有关,我想知道我们是否可以通过其他方式解决这个问题。
Any help is appreciated, thank you. 任何帮助表示赞赏,谢谢。
Instead of dct={}
just do this: 代替
dct={}
做到这一点:
from collections import OrderedDict
dct = OrderedDict()
The keys will be ordered in the same order you define them. 键将按照您定义键的顺序排列。
Comparative test: 对比测试:
from collections import OrderedDict
dct = OrderedDict()
dct['a']=[1,2,3,4]
dct['b']=[5,6,7,8]
dct['c']=[9,10,11,12]
stddct = dict(dct) # create a standard dictionary
print(stddct.keys()) # "wrong" order
print(dct.keys()) # deterministic order
result: 结果:
['a', 'c', 'b']
['a', 'b', 'c']
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