如何使用Regex从URL提取路径？

Question

I want to extract path from url.

www.abc.com/contact/abc => /contact 
www.abc.com/contact.abc/asdsad => /contact.abc
www.abc.com/contact-abc.html/asdsad => /contact-abc.html
www.abc.com/contact-2 => /contact-2
www.abc.com/contact-us => /contact-us
abc&/contact.abc&^ = /contact.abc

What single regex could do this?

Answer 1

\/([0-9a-zA-Z+.-]+)[\/&| ]

This one could be a solution, though it is strictly related to the urls you gave in your question as examples.

I'll leave you the link to regexr so that you can understand what is there actually behind.

Regexr resource

Answer 2

If you are using Java, use java.net.URL class to parse URL and getPath method to get its path as explained here, no need for regex:

https://docs.oracle.com/javase/tutorial/networking/urls/urlInfo.html .

For regex, refer to this in question:

Getting parts of a URL (Regex)