[英]Loop through 2D Array
I want to save two Strings in a 2D String Array and further use it for other methods. 我想在2D字符串数组中保存两个字符串,并进一步将其用于其他方法。
My Array: 我的阵列:
String[][] x = {{"Iron Ice Tea", "5"}, {"Clock Clock", "3"}, {"Shoe Telephone", "3"}};
My method: 我的方法:
public static String getInsertedCustomerOrder(String[][] input) {
String query = "";
int x = 0;
for (String[] product : input) {
for (String count : product) {
if (x == 0) {
query = query + "((SELECT PRICE FROM PRODUCT WHERE NAME = '" + product + "') * " + count + " + ";
} else {
query = query + "(SELECT PRICE FROM PRODUCT WHERE NAME = '" + product + "') * " + count + " + ";
}
x++;
}
}
if (query != null && query.length() > 0 && query.charAt(query.length() - 2) == '+') {
query = query.substring(0, query.length() - 2);
}
query = query + ")";
return query;
}
The output is: 输出是:
((SELECT PRICE FROM PRODUCT WHERE NAME = '[Ljava.lang.String;@1db9742') * Iron Ice Tea + (SELECT PRICE FROM PRODUCT WHERE NAME = '[Ljava.lang.String;@1db9742') * 5 + (SELECT PRICE FROM PRODUCT WHERE NAME = '[Ljava.lang.String;@106d69c') * Clock Clock + (SELECT PRICE FROM PRODUCT WHERE NAME = '[Ljava.lang.String;@106d69c') * 3 + (SELECT PRICE FROM PRODUCT WHERE NAME = '[Ljava.lang.String;@52e922') * Shoe Telephone + (SELECT PRICE FROM PRODUCT WHERE NAME = '[Ljava.lang.String;@52e922') * 3 )
Whereas it should be: 它应该是:
((SELECT PRICE FROM PRODUCT WHERE NAME = 'Iron Ice Tea') * 5))
Try this. 尝试这个。
public static String getInsertedCustomerOrder(String[][] input) {
boolean first = true;
String query = "";
for (String[] product : input) {
if (first)
first = false;
else
query += " + ";
query += "(SELECT PRICE FROM PRODUCT WHERE NAME = '" + product[0] + "') * "
+ product[1];
}
query = "(" + query + ")";
return query;
}
And 和
String[][] input = { { "Iron Ice Tea", "5" }, { "Clock Clock", "3" }, { "Shoe Telephone", "3" } };
System.out.println(getInsertedCustomerOrder(input));
Result: 结果:
((SELECT PRICE FROM PRODUCT WHERE NAME = 'Iron Ice Tea') * 5 + (SELECT PRICE FROM PRODUCT WHERE NAME = 'Clock Clock') * 3 + (SELECT PRICE FROM PRODUCT WHERE NAME = 'Shoe Telephone') * 3)
Could you please try below code snippet - 你可以试试下面的代码片段 -
String[][] x = {{"Iron Ice Tea", "5"}, {"Clock Clock", "3"}, {"Shoe Telephone", "3"}};
int lastIndex = x.length-1;
int currentIndex = 0 ;
String query = "";
for (String[] product : x) {
if(currentIndex == lastIndex)
query +="((SELECT PRICE FROM PRODUCT WHERE NAME = '"+product[0]+"') * "+product[1]+")";
else
query +="((SELECT PRICE FROM PRODUCT WHERE NAME = '"+product[0]+"') * "+product[1]+") + ";
currentIndex++;
}
System.out.println("query : "+query);
product 产品
x[0] = {"Iron Ice Tea", "5"} - is object so will get object hash code x [0] = {“铁冰茶”,“5”} - 是对象,因此将获得对象哈希码
x[1] = {"Clock Clock", "3"} - is object will get object hash code x [1] = {“时钟时钟”,“3”} - 对象将获取对象哈希码
x[2] = {"Shoe Telephone", "3"} - is object will get object hash code x [2] = {“Shoe Telephone”,“3”} - 对象将获取对象哈希码
first iteration 第一次迭代
product[0] = x[0][0] = "Iron Ice Tea" , product[1] = x[0][1] = "5" 产品[0] = x [0] [0] =“铁冰茶”,产品[1] = x [0] [1] =“5”
second iteration 第二次迭代
product[0] = x[1][0] = "Clock Clock" , product[1] = x[1][1] = "3" product [0] = x [1] [0] =“Clock Clock”,产品[1] = x [1] [1] =“3”
third iteration 第三次迭代
product[0] = x[2][0] = "Shoe Telephone" , product[1] = x[2][1] = "3" product [0] = x [2] [0] =“Shoe Telephone”,产品[1] = x [2] [1] =“3”
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.