从边列表中选择多个边属性值并放入列表[List]

Question

I am having vertices with multiple edges having same labels. Edges having properties like age1 , age2 and time in it.

Example:

A-->B => age1 = 10, age2 =10 and time = t1

A-->B => age1 = 20, age2 =30 and time = t1

A-->B => age1 = 30, age2 =50 and time = t1

I need to form two list[List[]] with the above the edges with specific time

eg : List[[10,10][20,30][30,50]]

graph.traversal.V().has(ID,"A").bothE("interference").
where(_.values("time").is(P.gt("sometime"))).values("age1").as("x").values("age2").as("y").select("x","y").toList()

It is giving some compilation error. Am i doing something wrong in the query

Compilation Error:

could not find implicit value for parameter p: shapeless.ops.hlist.Prepend[shapeless.HNil,shapeless.::[A,shapeless.HNil]] .where(_.values("time").is(P.gt(endtime))).values("age1").as("x")

Answer 1

Below solves this problem

Scala gremlin:

 graph.traversal.V().has(ID,"A").bothE("interference").
    where(_.values("time").is(P.gt("sometime"))).valueMap("age1","age2").toList()

Gremlin console:

graph.traversal().V().has('ID', 'a').bothE("interference").valueMap('age1','age2')
==>{age2=50, age1=10}
==>{age2=50, age1=30}
==>{age2=20, age1=60}