[英]how to convert date-time to epoch in python?
I want this particular date-time to be converted to epoch but it is giving me format error. 我希望将此特定的日期时间转换为纪元,但这给了我格式错误。 what format should i use to do the following so that it can be json rendered. 我应该使用哪种格式来执行以下操作,以便可以json呈现。 "2016-10-14 14:34:14+00:00". “ 2016-10-14 14:34:14 + 00:00”。 I am using python 2.7 and django 1.10 我正在使用python 2.7和Django 1.10
stra = "instance[0].Timing"
formata = "%Y-%m-%d %H:%M:%S+00:00"
timing = calendar.timegm(time.strptime(stra, formata))
return HttpResponse(json.dumps(
{'result': 'True'
'timing': timing,
}))
Option 1, you can use isoformat()
: 选项1,您可以使用isoformat()
:
from datetime import datetime
print(datetime.utcnow().isoformat())
# '2016-10-19T03:39:40.485521'
Option 2, strftime()
, do not confuse it with strptime
: 选项2, strftime()
,不要将其与strptime
混淆:
print(datetime.utcnow().strftime('%Y-%m-%d %H:%M:%S+00:00'))
# '2016-10-19 03:42:58+00:00'
Actually in django datetime object are converted in epoch as following way. 实际上在datego datetime对象中,按以下方式在纪元中进行了转换。
Emample 1 范例1
import datetime
current_date = datetime.datetime.now()
epoch = int(current_date.strftime("%s")) * 1000
Example 2 例子2
import datetime
date_object = datetime.datetime.strptime('Jun 1 2005 1:33PM', '%b %d %Y %I:%M%p')
epoch = int(date_object.strftime("%s")) * 1000
This is a literal string, it's not pulling data out of whatever instance you have: 这是一个文字字符串,它不是从任何实例中提取数据:
stra = "instance[0].Timing"
Perhaps you meant the following instead? 也许您的意思是以下内容?
stra = instance[0].Timing
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