C ++对文件夹中的所有文件执行相同的代码

Question

I have been surfing the net for really long time and I didn't even get close to any solution to this. Sorry if it seems trivial to experts.

I have a C++ code that takes a binary file as an input argument, does some computation then outputs a .csv file. So, I have been using the command line to execute the code over one or more files, as following

MyProgram filename1 filename2 

In my case, I have all my files from filename1 to filenameN in a specific folder. I want to know if there is any way to input the folder name, so the program would be executed over all the files included.

Maybe something like this

Myprogram /Users/Whatever

or in windows like

Myprogram C:\User\Whatever

Thanks in advance

Answer 1

For linux you can use command line with wild characters arguments like: YourProgram path/to/*.csv and you'll get all files match to the pattern path/to/*.csv into the argv array.

If it is windows you can use some Win API like FindFirstFile , FindNextFile to resolve the wild characters and get all match files. you can also check this example :

Answer 2

On *nix based consoles then the "xargs" command is your friend. eg

find ./MyDirectory -name "*.notcsv" | xargs myprogram

Personally I wouldn't modify the code itself to iterate through files as the operating system supplies a mechanism. It makes your program more "single responsibility". If you send the output to stdout/cout it allows your program to be chained with other text processing commands if necessary.

Cheers