[英]How do I treat a special string as an array and select the second object from it in postgreSQL
I have a column in my table which has values like this 我的表格中有一列具有这样的值
1923195445602;182343;en
or 要么
1830310365602;175824;en;EVENT
Data is split by ";" 数据用“;”分隔
I want to select the second value of it. 我想选择它的第二个值。 My thought is to find a way to treat this string as an array.
我的想法是找到一种将该字符串视为数组的方法。 Or is there a better way?
或者,还有更好的方法?
您可以使用select split_part(colname,';',2);
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