How do I treat a special string as an array and select the second object from it in postgreSQL

Question

I have a column in my table which has values like this

1923195445602;182343;en

or

1830310365602;175824;en;EVENT

Data is split by ";"

I want to select the second value of it. My thought is to find a way to treat this string as an array. Or is there a better way?

Answer 1

您可以使用select split_part(colname,';',2);