[英]Python remove 'text' from lists made by xlrd
I used xlrd to read through each cell of three columns to make three lists. 我使用xlrd读取了三列的每个单元格,从而形成了三个列表。 Then, I appended the ith element of all three lists to a new list, making a new list of lists.
然后,我将所有三个列表的第i个元素附加到新列表中,从而创建了一个新的列表列表。
search_terms=[]
for row in range(0, book.nrows):
search_terms.append([med_name[row], med_school[row], mentor[row]])
print(*search_terms[0:15], sep='\n')
[text:'Andrew Burkeland', 'Weill Cornell Medical College', 'Dave Cutler ']
[text:'Andrew Pence', 'University of Alabama at Birmingham School of Medicine', 'Jack Warran ']
Is there a way to take out the 'text:'? 有没有办法删除“文本:”? I am inputing each list in
search_terms
into Entrez.egquery
to search for results on pubmed
, and with 'text:' in the query line, I keep on getting 0 results. 我将
search_terms
每个列表输入到Entrez.egquery
以搜索pubmed
结果,并且在查询行中使用“ text:”,我一直得到0个结果。
Let's assume a simple table which is called 'students.xlsx' 让我们假设一个简单的表叫做“ students.xlsx”
Student School Mentor
John Doe Harvard Kornberg
Jane Done Stanford Pauling
and now open it with xlrd
现在用
xlrd
打开它
import xlrd
xl_workbook = xlrd.open_workbook('students.xlsx')
xl_sheet = xl_workbook.sheet_by_index(0)
row = xl_sheet.row(1)
Now let's look at the individual parts 现在让我们看一下各个部分
print(row)
[text:'John Doe', text:'Harvard', text:'Kornberg']
print(row[0])
text:'John Doe'
print(row[0].value)
'John Doe'
The problem is that row[0]
is an xlrd cell and not a string which is reason why it is necessary to get the content via value
. 问题是
row[0]
是xlrd单元格,而不是字符串,这就是为什么有必要通过value
获得内容的原因。
Now let's do it for all rows (except the header): 现在让我们对所有行(标头除外)执行此操作:
raw_data = list()
for row in range(1, xl_sheet.nrows):
raw_data.append(xl_sheet.row(row))
author_list = list()
for raw in raw_data:
author_list.append(list())
for r in raw:
author_list[-1].append(r.value)
print(author_list)
> [['John Doe', 'Harvard', 'Kornberg'], ['Jane Done', 'Stanford', > 'Pauling']]
or short: 或简称:
author_list = [[c.value for c in xl_sheet.row(n)] for n in range(1, xl_sheet.nrows)]
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