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如果子div包含某个数据属性,则删除父div

[英]Remove parent div if child div contains a certain data attribute

Since, I'm doing this dynamically, I have to check whether the main div matches a certain user-id . 由于我是动态进行的,因此我必须检查main div是否与某个user-id匹配。 If it does, then dive into it and do the extra work. 如果是这样,请深入其中并做额外的工作。 Let me show you what i'm talking about. 让我告诉你我在说什么。

<div class="col-md-6 user-card-holder" data-user="2">
  <div class="col-xs-2 single-card">
    <div class="house" data-house="hearts" data-value="q">Q-hearts</div>
  </div>
</div>

There are many div's having the classname user-card-holder . 有许多div's具有类名user-card-holder I have to check the specific one with the data-user attribute. 我必须使用data-user属性检查特定的对象。 Now what I'm checking is: 现在我正在检查的是:

If a div contains data-house with the value of hearts and also data-value with the value of q , then remove that div along with it's parent. 如果div包含具有hearts值的data-house以及具有q值的data-value ,则将该div及其父级移除。 Here parent means the div having the class single-card and not the user-card-holder 这里的parent是指具有single-card类而不是user-card-holderdiv

I have tried using filter() . 我尝试使用filter() Maybe I'm doing something wrong here. 也许我在这里做错了。

 $('.user-card-holder[data-user='+ card.user +'] div div').filter(function(){

     var div = $(this).data('house') == card.house && $(this).data('value') == card.number;
      return div.parent()


     }).remove();

I have seen answers which shows to remove the element based on data attribute, but not it's parent. 我已经看到了答案,该答案显示了根据data属性删除元素,但不是父元素。

I'd suggest: 我建议:

// this finds all <div> elements with a
// 'data-house' attribute equal to 'hearts' and a
// 'data-value' attribute equal to 'q':
$('div[data-house=hearts][data-value=q]')
  // traverses to the parent of the matching element(s):
  .parent()
  // removes the parent element(s) from the DOM:
  .remove();

Alternatively, if you're searching an ancestor dynamically to find the appropriate element(s) to remove, which seems to be the case on a re-reading of your question: 另外,如果您正在动态搜索祖先以找到要删除的适当元素,那么在重新阅读您的问题时似乎就是这种情况:

// finds <div> element(s) with the class of 'user-card-holder'
// and the 'data-user' attribute equal to the value of the 'card.user'
// variable, and finds the descendant <div> element(s) matching
// the selector used above:
$('div.user-card-holder[data-user=' + card.user + '] div[data-house=hearts][data-value=q]')
  // traverses to the parent of the descendant element:
  .parent()
  // removes the parent element of that descendant:
  .remove();

References: 参考文献:

Try this function: 试试这个功能:

removeCardFromUser(2);

function removeCardFromUser(id) {
    $('.user-card-holder').filter(function(){
        var user = $(this).data('user');
        if (user === id) {
            $(this).find('div').filter(function(){
                var house = $(this).data('house');
                var value = $(this).data('value');
                if (house === 'hearts' && value === 'q') {
                    $(this).parent().remove();
                }
            });
        }
    });
}

It looks for a div with class 'user-card-holder' and data-user = {given id} and then looks for its descendants with data-house = 'hearts' and data-value='q' and deletes its parent. 它使用类'user-card-holder'和data-user = {given id}查找div,然后使用data-house ='hearts'和data-value ='q'查找其后代并删除其父级。

David's answer would suffice though! 大卫的答案就足够了! :) :)

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