[英]How to assign an int to unsigned long using C?
I am using C language. 我正在使用C语言。 There is a function named "npu_session_total".
有一个名为“ npu_session_total”的函数。 Then, I will use the return value of this func and assign it to an unsigned long variable "accelerated_count".
然后,我将使用此func的返回值,并将其分配给一个无符号的长变量“ accelerated_count”。
int npu_session_total(void)
{
// this will return an int
return atomic_read(&npu_session_count);
}
........
unsigned long accelerated_count = npu_session_total();
Will this cause any problems? 这会引起任何问题吗? How can I do the cast?
我该怎么做演员?
Thanks! 谢谢!
Assigning an int
to a unsigned long
can be done simply as OP did. 可以像OP一样简单地将
int
分配给unsigned long
。 It is well defined in C. When some_int_value >= 0
it will always fit unchanged into an unsigned long
. 它在C中定义良好。当
some_int_value >= 0
,它将始终保持不变,成为unsigned long
。
INT_MAX <= UINT_MAX <= ULONG_MAX
No cast, masking, nor math is needed - just like OP did. 就像OP一样,不需要强制转换,遮罩或数学运算。
unsigned long some_unsigned_long_object = some_int_value;
The trick is when some_int_value < 0
. 诀窍是当
some_int_value < 0
。 The value saved will be some_int_value + ULONG_MAX + 1
. 保存的值将为
some_int_value + ULONG_MAX + 1
。 @AnT Now is this OK for OP's code? @AnT现在可以使用OP的代码了吗? Perhaps not.
也许不是。
A safer conversion would test for negativeness first. 较安全的转换会首先测试否定性。
int session_total = npu_session_total();
if (session_total < 0) {
Handle_Negative_Case(session_total);
}
else {
unsigned long accelerated_count = npu_session_total();
...
}
@OP comments that the int
value should never be negative. @OP注释
int
值永远不应为负。 Defensive coding would still detect negative values and handle that. 防御性编码仍将检测负值并进行处理。 Maybe a simple error message and exit.
也许是一个简单的错误消息并退出。
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