[英]how to return value from nested array - swift 3
My api query is returning several values in an array (as below), which I need to use for further functions. 我的api查询正在数组中返回多个值(如下所示),我需要将其用于其他功能。 How do I retrieve the value 60, which is nested?
如何获取嵌套的值60?
My code eg let uid = value["uid"] as? String
我的代码例如,
let uid = value["uid"] as? String
let uid = value["uid"] as? String
works well to return uid and name. let uid = value["uid"] as? String
可以很好地返回uid和name。 But for let rest = value["field_resting_bpm"] as? String
但是,
let rest = value["field_resting_bpm"] as? String
let rest = value["field_resting_bpm"] as? String
it returns nil. let rest = value["field_resting_bpm"] as? String
返回nil。
How do I correct this line to return the nested value '60'?: 如何更正此行以返回嵌套值“ 60” ?:
let rest = value["field_resting_bpm"] as? String'
the api query is: api查询为:
let credentialData = "\(user):\(password)".dataUsingEncoding(NSUTF8StringEncoding)!
let base64Credentials = credentialData.base64EncodedStringWithOptions([])
let headers = ["Authorization": "Basic \(base64Credentials)"]
var checkUserEndpoint: String = " https://example.site/ios1/user/1.json " var checkUserEndpoint:字符串=“ https://example.site/ios1/user/1.json ”
Alamofire.request(.GET, checkUserEndpoint, parameters: nil, headers: headers, encoding: .JSON)
.responseJSON { response in
guard response.result.error == nil else {
print("ran alamofire")
//got an error in getting the data, need to handle it
print("error calling GET")
print(response.result.error!)
return
}
guard let value = response.result.value else {
print("no result data received when calling GET")
return
}
// return UID
print("ran alamofire")
var datareturned = JSON(value)
print("VALUE: \(value)")
it returns this in my console: 它在我的控制台中返回:
uid = 1;
name = "Guest User";
"field_resting_bpm" = {
und = (
{
value = 60;
}
);
UPDATE: this field is an Integer in Drupal user account settings. 更新:此字段是Drupal用户帐户设置中的整数。 I have added a text field (so it should return a string), named field_rest_bpm_string, also for testing
我添加了一个名为field_rest_bpm_string的文本字段(因此它应该返回一个字符串),也用于测试
the json on the site returns: 网站上的json返回:
"field_resting_bpm":{"und":[{"value":"60"}]},"field_rest_bpm_string":{"und":[{"value":"65","format":null,"safe_value":"65"}]} “ field_resting_bpm”:{“ und”:[{“ value”:“ 60”}]},“ field_rest_bpm_string”:{“ und”:[{“ value”:“ 65”,“ format”:null,“ safe_value” :“ 65”}]}
NOTE : Code is in Swift 3 but you can easily convert that in swift 2. SwiftyJSON
version code is same in 2 and 3. 注意 :代码在Swift 3中,但是您可以轻松地在swift 2中进行转换
SwiftyJSON
版本代码在2和3中相同。
If you are using SwiftyJSON
then things are pretty much simpler 如果您使用的是
SwiftyJSON
那么事情就简单得多
let value = datareturned["field_resting_bpm"]["und"][0]["value"].stringValue
print(value)
If you are not using SwiftyJSON
如果您不使用
SwiftyJSON
let rest = value["field_resting_bpm"] as? NSDictionary
let und = (rest?.value(forKey: "und") as! NSArray).object(at: 0) as! NSDictionary
let yourValue = und.value(forKey: "value") as! String
Something like this. 这样的事情。
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