正则表达式允许为空或1到9位数字

Question

I have tried to validate my input quantity field by using pattern attribute. But my regular expression not working. Please check

^(?:[1-9]\d*|)$

Please anyone help me. My input field should accept null or 1 to 9 digit. Not accept 0 or any letter and symbol.

AngulrJS code:

<input class="form-control" name="quantity" ng-model="quoteList.quantity" placeholder="Quantity" required="" min="1" ng-pattern="/^(?:[1-9]\d*|)$/">
<div ng-show="userForm.$submitted || userForm.quantity.$touched">
    <span ng-show="userForm.quantity.$error.pattern" class="text-danger">Not valid number!</span>
</div>

Answer 1

If you want to match multiple numbers 1-9 use:

^[1-9]*$

This regex is as good as it gets with regard to checking for NULL values. If you want to also allow nulls, then you should include this logic explicitly in your controller, ie

form.input.$valid || quoteList.quantity === null

Update:

It appears that what you really wanted to ask is how to validate a number which begins with 1-9 , but then can be followed by any digit. If so, then try this regex:

^[1-9][0-9]*$

Again, you can check in your controller for null values and also allow them too.

Answer 2

You may check by yourself:

https://regex101.com ^(?:[1-9]\\d*|)$

Answer 3

^(?:[1-9]*)$

应该足够了。