[英]get ajax response in jquery modal form dialog
I can't get the ajax response when submitting a modal dialog form. 提交模态对话框表单时,我无法获得ajax响应。 It works perfectly when the form is not modal.
当表单不是模态时,它可以完美工作。
The form: 表格:
<div id="form2" style="display: none">
<form id="objectInsert" action="element/create" method="POST" enctype="multipart/form-data">
<div class="form-group">
<label for="name">Name</label>
<input class="form-control" type="text" name="name" id="name"/>
</div>
<div class="form-group">
<label for="description">Description</label>
<textarea class="form-control" name="description"></textarea>
</div>
</form>
Here i get the ajax success part in the console! 在这里,我在控制台中获得了ajax成功部分!
$("#objectInsert").submit(function(e) {
e.preventDefault();
resetErrors();
var form = this;
var url = $(this).attr('action');
var data = new FormData($(this)[0]);
$.ajax({
type: 'POST',
url: url,
data: data,
dataType: 'json',
cahe:false,
processData: false,
contentType: false,
success: function(resp) {
console.log(resp);//Working
},
error: function() {
console.log('there was a problem checking the fields');
}
});
});
Here i get the ajax error part in the console! 在这里,我在控制台中获得了ajax错误部分! can someone tell me where i'm doing wrong?
有人可以告诉我我做错了什么吗?
$("#add_element").click(function(){
$("#form2").dialog({
modal:true,
width:400,
buttons:{
Send:function(e){
e.preventDefault();
var form = $("#objectInsert");
var url = form.attr('action');
var data = new FormData(form[0]);
$.ajax({
type: 'POST',
url: url,
data: data,
dataType: 'json',
cahe:false,
processData: false,
contentType: false,
success: function(resp) {
console.log(resp);//not working
},
error: function(xhr, status, error) {
console.log('there was a problem checking the fields');
console.log(xhr);
console.log(error);
}
});
return false;
},
Cancel:function(){
$(this).dialog("close");
}
}
});
});
The controller 控制器
public function create() {
try{
$this->form = new Form();
$this->form->post('name');
$this->form->val('isEmpty', 'name');
$this->form->post('description');
$this->form->val('isEmpty', 'description');
$this->form->fetch();
$this->form->submit();
$data = $this->form->get_postData();
$this->model->insert($data);
echo json_encode('success');
} catch (Exception $ex) {
$errors = $this->form->get_error();
$_SESSION["errors"] = $errors;
//This is for ajax requests:
if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) &&
strtolower($_SERVER['HTTP_X_REQUESTED_WITH'])
== 'xmlhttprequest') {
echo json_encode($_SESSION['errors']);
exit;
}
foreach ($_SESSION["errors"] as $errors){
echo $errors;
echo '<br/>';
}exit;
}
}
see this code you have not closed the function block 看到此代码,您尚未关闭功能块
success: function(resp) {
console.log(resp);//not working
},//This is not closed for success function
error: function() {
console.log('there was a problem checking the fields');
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.