C ++ void指针获取结构

Question

I'm trying to learn void pointer. I want to get the passed struct contents using a void pointer.

Here is my struct:

Main.cpp

struct mynode
{
    int id;
    int amt;
};
struct mynode* myNode;

int main()
{   
    myclass mc;
    mc.initialize(myNode);
    getch();
}

myclass.cpp

void initialize(void* data)
{
    //how to get passed struct here ?
}

Answer 1

well, you can cast the pointer back to the original structure:

auto myStruct = static_cast<mynode*>(data);

although, your code is terribly C-like in the use of void* .

In C++, you are encouraged to use static polymorphism in the form of templates:

template<class Dependency>
void initialize(Dependency& data){/*...*/}

or dynamic polymorphism, in the form of inheritance and overriding:

struct BaseNode{
  virtual ~BaseNode() = default;
};

struct MyNode : public BaseNode{};

void initialize (BaseNode* node){/*..*/};

The use of void* in order to achieve generic code in C++ usually comes when dealing with C API's, like POSIX or Win32, and in your code you should avoid them.