像C ++一样读取Java中的字符？

Question

I have an input like

...
...
..# 

if read in c++ it would be like:

int main() {
    char c;

    int n = 9;

    while(n--) {
       cin >> c;
    }
  return 0;
}

but in java I have tried doing:

public static void main(String args[]) {

    Scanner s =  new Scanner(System.in);
    int n = 9;
    char c;
    while(n--) {

        c = s.next().chartAt(0);

    }

}

it skips dots, I mean it only reads the first dot of each line.

There is not space between each dot.

Answer 1

When I was learning Java a long time ago, I always used this method to read a single character:

char c = s.findWithinHorizon(".", 0).charAt(0);

where s is the scanner.

After some testing, I found that this doesn't read new line characters! So this code works!

String input = "...\n...\n..#";
Scanner s = new Scanner(input);
for (int i = 0 ; i < 9 ; i++) {
    char c = s.findWithinHorizon(".", 0).charAt(0);
    // do whatever you want with c here
}