从XSL中的XML文件中提取单个元素的值

Question

I have below xml file and i want to extract a single element from any node,

<?xml version="1.0" encoding="UTF-8"?>
<root>
    <SubRoot>
        <type>A</type>
        <mand>Y</mand>
        <Section>B</Section>
    </SubRoot>
    <SubRoot>
        <type>B</type>
        <mand>Y</mand>
        <Section>A</Section>
    </SubRoot>
</root>

From the above xml file how can i get the value of type element from any SubRoot node in XSL.And number of SubRoot node is unknown.it can be one,two,three or more than three. I don't want to use the template and for each loop.

i tried something as below but i am not getting any value

<xsl:if test="(/root/SubRoot/[Section = 'B'])">
 <xsl:value-of select="/root/SubRoot/@type"/>
 </xsl:if>

Please suggest me some approach.Any suggesstion and solution must be appreciated.

Answer 1

Suppose i want to select type from second node

Use:

<xsl:value-of select="/root/SubRoot[2]/type"/>

to extract the type value from the second SubRoot node.

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Judging from your attempt, you want the type value from the SubRoot node where Section has the value of "B". For this, use:

<xsl:value-of select="/root/SubRoot[Section='B']/type"/>