逗号分隔的值转换为单引号和逗号分隔的值

Question

I have data as

    abc,defg,hijklm,op,qrs,tuv

I want this data to be converted to

    'abc','defg','hijklm','op','qrs','tuv'

I want to do in linux. I used "sed". I have been looking all over internet,but didnot come across a solution. Please help me.

Answer 1

Add a single quote at start ( ^ ) & end ( $ ), and replace comma by quote-comma-quote (like you did) using sed with 3 expressions (using -e option to specify them):

echo  abc,defg,hijklm,op,qrs,tuv | sed -e "s/^/'/" -e "s/\$/'/" -e "s/,/',\'/g" 

(also: protect single quotes with double quotes)

results in:

'abc','defg','hijklm','op','qrs','tuv'

in awk (maybe a little clumsy), generally better since field parsing is handled natively by awk :

echo  abc,defg,hijklm,op,qrs,tuv | awk -F, "{for (i=1;i<=NF-1;i++) printf(\"'%s',\",\$i); printf(\"'%s'\",\$i);}"

(print all fields plus comma except for the last one)

Answer 2

Using awk gsub function. Here all the " , " are replaced by ',' and start and the end of the line is replaced by " ' ".

echo $x |awk -v q="'" '{gsub(/,/, q "&" q);gsub(/^|$/,q)}1'
'abc','defg','hijklm','op','qrs','tuv'

Answer 3

awk '{gsub(/,/,"\47,\47");print "\47"$0"\47"}' file

'abc','defg','hijklm','op','qrs','tuv'

Answer 4

另一个awk

$ awk -F, -v OFS="','" -v q="'" '{$1=q $1; print $0 q}' file