如何在bash中对逗号分隔值进行排序？

Question

I have some numbers like

7, 15, 6, 2, -9

I want to sort it like this in bash(from command line or either a script file)

-9, 2, 6, 7, 15

How can I do this? I am unable to get this using sort command.

Answer 1

echo "7, 15, 6, 2, -9" | sed -e $'s/,/\\\n/g' | sort -n | tr '\n' ',' | sed 's/.$//'

1. sed -e $'s/,/\\\\\\n/g' : For splitting string into lines by comma.
2. sort -n : Then you can use sort by number
3. tr '\\n' ',' : Covert newline separator back to comma.
4. sed 's/.$//' : Removing tailing comma.

Not elegant enough, but it should work :p

Answer 2

With perl

$ s='7, 15, 6, 2, -9'
$ echo "$s" | perl -F',\h*' -lane 'print join ", ", sort {$a <=> $b} @F'
-9, 2, 6, 7, 15
$ echo "$s" | perl -F',\h*' -lane 'print join ", ", sort {$b <=> $a} @F'
15, 7, 6, 2, -9

• -F',\\h*' use , and optional space/tab as field separator
  • see https://perldoc.perl.org/perlrun.html#Command-Switches for explanation of command line options
• sort {$a <=> $b} @F sort the array numerically, in ascending order... use sort {$b <=> $a} @F' for descending order
• join ", " tells how to join the array elements before passing on to print

Answer 3

To summarize answers and comments, this works and maintains spaces:

echo "7, 15, 6, 2, -9" | sed -e $'s:,:\\\\\\n:g' | sort -n | paste -sd ',' - | sed 's:,:, :g'

Note that you may be able to get away with sed -e 's:,:\\n:g' instead of the first sed call. This works on my system running bash version 4.2.46 with sed version 4.2.2. To remove the spaces (or if they're unnecessary), remove the final sed call and pipe.