我收到错误通知：我的代码php中的数组到字符串的转换

Question

hi guys i got problem in my code i don't know where come form this my code

<h1><?php echo $item["title"]; ?> </h1>
       <table>
          <tr>
             <th>Catageory</th>
             <td><?php echo $item["category"]; ?></td>
         </tr> 
         <tr>
             <th>Genre</th>
             <td><?php echo $item["genre"]; ?></td>
         </tr> 
         <tr>
             <th>Format</th>
             <td><?php echo $item["format"]; ?></td>
         </tr> 
         <tr>
             <th>Year</th>
             <td><?php echo $item["year"]; ?></td>
         </tr> 
         <?php
         if(strtolower($item["category"]) == "books"){
             ?>
        <tr>
             <th>Authors</th>
             <td><?php echo $item["authors"]; ?></td>
         </tr> 

        <tr>
             <th>Publisher</th>
             <td><?php echo $item["publisher"]; ?></td>
         </tr> 
        <tr>
             <th>ISBN</th>
             <td><?php echo $item["isbn"]; ?></td>
         </tr>           

    <?php    }  ?>

And the error message,

and Iam sure all code are same i don't what's problem !!

Answer 1

As per your image, you are trying to print string on line 58, but you are getting array from your resultant query. So try to var_dump($yourvar) and check that are you getting required string or an array

Answer 2

You are trying to echo an array variable which is not right. Use the below debug code and you have to parse the array however you want.

    Authors ->  <?php echo "<pre>";print_r($item["authors"]);echo "<pre>"; ?>

Answer 3

my problem is solved

by replace

             <td><?php echo $item["authors"]; ?></td>

to

<td><?php echo implode(",", $item["authors"]); ?></td>