无法将不可变值作为inout参数传递：来自'UnsafePointer的隐式转换 <UInt8> ？ 到'UnsafePointer <UInt8> ？ 需要一个临时的
[英]Cannot pass immutable value as inout argument: implicit conversion from 'UnsafePointer<UInt8>? to 'UnsafePointer<UInt8>?' require a temporary
问题描述
I have written a method for parsing Receipt of InAppPurchase in Swift2.3 and now I am converting it to Swift3 . 
我在Swift2.3编写了一个解析InAppPurchase Receipt的方法，现在我将它转换为Swift3 。 So I am getting this error. 所以我收到了这个错误。 Anyone has idea, how to fix this? 任何人都有想法，如何解决这个问题？
1 个解决方案
解决方案1
0 已采纳 2016-12-01 13:05:06
试试这样，
var p: UnsafePointer<UInt8>? = (data as NSData).bytes.bindMemory(to: UInt8.self, capacity: data.count)
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