从UInt8到UInt8 []的类型转换给出错误

Question

I've defined a struct like so:

typedef struct __attribute__((packed)) {
    UInt8  a;
    UInt16 b;
    UInt8  c[15];
} myStruct;

When I try to get value

UInt8  c = packet->c;

I receive the following error

Incompatible pointer to integer conversion initializing 'UInt8' (aka 'unsigned char') with an expression of type 'UInt8 [15]

What type do I need to cast to in order to compile? I have tried adding [15] subscript in different places and could not solve it. Also an explanation of what [15] means in UInt8 c[15];

Thanks

Answer 1

I guess packet is declared as myStruct packet; . If so, packet->c is an array of UInt8 , you can store up to 15 items in this member. That's why you cannot assign it's value to a single UInt8 . Replace UInt8 c = packet->c; with UInt8* c = packet->c; . To get the first c 's item use the following code: UInt8 firstC = c[0]; .