[英]How to create an array with a simple for loop?
I need to create an array that looks like this: 我需要创建一个如下所示的数组:
[0,0,1,1,2,2,3,3,4,4....]
Given my following code, how can I eliminate the counter
? 鉴于我的以下代码,我该如何消除counter
?
int[] SomeArray = new int[24];
int counter = 0;
for(int x = 0 ; x < SomeArray.length-1 ; x++){
SomeArray[x] = counter;
SomeArray{x+1] = counter;
counter++;
}
In Java 8+, you could use an IntStream.range(int, int)
and map
each value as desired. 在Java 8+中,您可以使用IntStream.range(int, int)
并根据需要map
每个值。 Something like, 就像是,
int[] someArray = IntStream.range(0, 24).map(x -> {
return x / 2;
}).toArray();
Also, please follow Java variable naming conventions ( someArray
, not SomeArray
). 另外,请遵循Java变量命名约定( someArray
,而不是SomeArray
)。
If you have to use Java 7 (or earlier), then you can do it with something like 如果你必须使用Java 7(或更早版本),那么你可以使用类似的东西
int[] someArray = new int[24];
for (int i = 0; i < someArray.length; i++) {
someArray[i] = i / 2;
}
use increment x=x+2 as two indexes of array are being stored in every iteration 使用增量x = x + 2作为数组的两个索引存储在每次迭代中
for(int x = 0 ; x < SomeArray.length-1 ; x+=2){
SomeArray[x] = x/2;
SomeArray[x+1] = x/2;
}
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