[英]How to check if a pair exists using HQL in query?
I have a list of different ids and their names. 我列出了不同的ID及其名称。 For every id[0]
we have name[0]
that needs to be matched. 对于每个id[0]
我们都需要匹配name[0]
。
l{1,2,3,4};
ids列表, l{1,2,3,4};
n{a,b,c,d};
名单, n{a,b,c,d};
Now suppose if I want to get an exact match for both above combination, is there any way in HQL to get the result? 现在假设我想要获得上述两种组合的完全匹配,是否有任何方法可以在HQL中获得结果?
I am looking to find a replacement for a query like: 我希望找到一个像以下查询的替代品:
select any_column
from table_name
where (id[0]=1 and name[0]=a) or (id[1]=2 and name[1]=b and so on...);
The HQL query should be something like below: HQL查询应如下所示:
select any_column
from table_name
where (id,name) IN {(id[0],name[0]), (id[1], name[1]),...};
Any suggestions? 有什么建议么?
I am not hql/sql guy, however one way I can think of is, in your hql, you concatenate the id and name with a space (or other special char) then with in
sub-clause. 我不是HQL / SQL的家伙,但我能想到的是单向的,在你的HQL,您连接ID和名称用空格(或其他特殊字符),然后用in
子条款。 something like: 就像是:
select * from table where concat(id, ' ', name) in (:pairList)
The pairList
parameter is a java collection, you should prepare before the hql query call, which has element id[x] + " " + name[x]
. pairList
参数是一个java集合,你应该在hql查询调用之前准备,它有元素id[x] + " " + name[x]
。
I think this should work. 我认为这应该有效。
If you are using hibernate, another possible solution is, make use of the hibernate's @Formular
annotation on your table
entity, to create a calculated column, such as: 如果你正在使用hibernate,另一种可能的解决方案是,在你的table
实体上使用hibernate的@Formular
注释来创建一个计算列,例如:
@Formula(value = " concat(id, ' ', name) ")
private String idNamePair;
Then you can in hql use it as a normal field. 然后你可以在hql中将它用作普通字段。 like ... from table where idNamePair in (:paramList)
喜欢... from table where idNamePair in (:paramList)
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