[英]Python call a function many times with different arguments
I have a function that takes two arguments. 我有一个带有两个参数的函数。 I want to run the function for every possible combination of my inputs, and store each returned value.
我想为输入的每种可能的组合运行该函数,并存储每个返回的值。 For example:
例如:
def foo(a, b):
return (a + b)
if __name__ == "__main__":
a = np.array([1., 2., 3.])
b = np.array([5., 6.])
f1 = foo(a[0], b[0]) #6
f2 = foo(a[0], b[1]) #7
f3 = foo(a[1], b[0]) #etc
f4 = foo(a[1], b[1])
f5 = foo(a[2], b[0])
f6 = foo(a[2], b[1])
How can I call f1 through f6 in a more elegant way, like a loop? 如何以更优雅的方式(如循环)调用f1至f6? It can't be a direct loop, because a and b have differing numbers of elements.
它不能是直接循环,因为a和b具有不同数量的元素。
itertools.product
is the way to go in a Pythonic manner. itertools.product
是采用Python方式的一种方式。 However, if you are looking for a more raw, basic way, you'll need two for loops, which is the basic property of a cross product. 但是,如果您正在寻找一种更原始的基本方法,则需要两个for循环,这是叉积的基本属性。
for i in a:
for j in b:
foo(i, j)
Edit: 编辑:
Example usages of itertools.product
: itertools.product
用法示例:
for i, j in itertools.product(a, b):
foo(i, j)
for tup in itertools.product(a, b):
foo(*tup)
I prefer the first one because tuple's elements can be used explicitly if needed. 我更喜欢第一个,因为如果需要,可以显式使用元组的元素。
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