返回查询结果的函数
[英]function that return query result
问题描述
assume that i have a table named mytable with columns: 
假设我有一个名为mytable的表，其中包含列：
------------------------
| id | field1 | field2 |
------------------------
and assume i have a html files: 并假设我有一个HTML文件：
<body>
<?php
include ('connect-db.php');
include ('function.php');
?>
<ul>
<?php
myfunction();
while($row = $result->fetch_assoc()){
echo "<li>".$row['field1']." and ". $row[field2]."</li>";
}
?>
</ul>
</body>
this is my connect-db.php file: 这是我的connect-db.php文件：
<?php
$servername = "localhost";
$username = "root";
$password = "root";
$dbname = "dbname";
$conn=new mysqli($servername, $username, $password, $dbname);
?>
and this is my function.php file: 这是我的function.php文件：
<?php
function myfunction(){
$sql = "SELECT * FROM mytable";
$result = $conn->query($sql);
}
?>
How to echo the field1 and field 2? 如何回显field1和field 2？ because i have and error 因为我有错误
2 个解决方案
解决方案1
0 已采纳 2016-12-11 10:47:02
Any variable used inside a function is by default limited to the local function scope.
You can read more about it here: Variable scope . 您可以在此处阅读更多相关信息： 可变范围 。 How to fix it? 怎么解决？ Pass the $conn as an argument of myfunction , and return the $result . 传递$conn作为myfunction的参数，并返回$result 。
function myfunction(mysqli $conn) {
$sql = "SELECT * FROM mytable";
return $conn->query($sql);
}
then you can call it with 然后你可以用它来调用它
$result = myfunction($conn);
解决方案2
0 2016-12-11 10:49:27
Make sure the following changes..... 确保以下更改.....
at main page 在主页面
<body>
<?php
include ('connect-db.php');
include ('function.php');
?>
<ul>
<?php
$result= myfunction();
while($row = $result->fetch_assoc()){
echo "<li>".$row['field1']." and ". $row[field2]."</li>";
}
?>
</ul>
</body>
At your function file.. 在你的功能文件..
<?php
include ('connect-db.php');
function myfunction(){
$sql = "SELECT * FROM mytable";
$result = $conn->query($sql);
return $result;
}
?>
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